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Taya2010 [7]
3 years ago
6

Technician A says that if starter drive clearance is too small, the starter will produce a noise during cranking. Technician B s

ays that if starter drive clearance is too large, the starter will produce a noise after cranking. Which technician is correct?

Physics
1 answer:
Ronch [10]3 years ago
8 0

Answer:

Both Technicians A and B are wrong in there answers.

Explanation:

Starter Drives are rotating mechanical component use to drive another component (flywheel) to start an engine. And thus they are known as starters. Starters are smaller than the component they drive. They are found commonly in automobiles.

The starter and the driven component(gear) are supposed to fit closely, with some clearance between the two gears so as to operate without noise. When the<u> clearance is too small </u>there will be a <u>noise after cranking,</u>  and   when the <u>clearance is too great</u> there be <u>noise before cranking</u>.

Cranking simply means starting an engine or the initial rotating of an engine to start it.  

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In a double slit experiment, if the separation between the two slits is 0.050 mm and the distance from the slits to a screen is
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The spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

<h3>What is double slit experiment?</h3>

The double-slit experiment serves as a proof in current physics that both light and matter may exhibit properties of classically defined waves and particles. It also illustrates the inherently probabilistic nature of quantum mechanical events. Thomas Young carried out the first experiment of this kind employing light in 1802, illustrating how light behaves like a wave. It was formerly believed that light was made up of either waves or particles. About a century later, with the advent of modern physics, it was discovered that light may in fact exhibit behaviour like that of both waves and particles. The identical behaviour of electrons was first shown by Davisson and Germer in 1927, and it was later extended to atoms and molecules.

The separation between the slits, d = 0.05mm = 5×10⁻⁵ m

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Let x is the spacing between the first-order and second-order bright fringes when coherent light of wavelength 600 nm illuminates the slits,

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We know that the bright fringe is given by :

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So, the spacing between the first-order and second-order bright fringes is 3 cm. Hence, this is the required solution.

to learn more about double slit experiment go to -

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