Ask question

Ask question

All categories

3 years ago

9

On the planet Gizmo, the inhabitants travel by high speed trains that run on air tracks much like the air track you used in lab.

A train car with a mass of 8700 kg is traveling at 11.0 m/s when it strikes a second car moving in the same direction at 2.2 m/s. The two stick together and move off with a speed of 4.00 m/s. What is the mass of the second car?

1 answer:

Shtirlitz [24]3 years ago

8 0

Answer:

$m_2=33833.33\ kg$

Explanation:

It is given that,

Mass of the train car, $m_1=8700\ kg$

Initial speed of the train car, $u_1=11\ m/s$

Initial speed of the second car, $u_2=2.2\ m/s$

After the collision, both cars stick together and move off with a speed of 4.00 m/s, V = 4 m/s

Let $m_2$ is the mass of the second car. It can be calculated using the conservation of momentum. In case of inelastic collision, after collision both objects move with a common speed.

$m_1u_1+m_2u_2=(m_1+m_2)V$

$m_1u_1+m_2u_2=m_1V+m_2V$

$m_1(u_1-V)=m_2(V-u_2)$

$m_2=\dfrac{m_1(u_1-V)}{(V-u_2)}$

$m_2=\dfrac{8700(11-4)}{(4-2.2)}$

$m_2=33833.33\ kg$

So, the mass of the second car is 33833.33 kg. Hence, this is the required solution.

You might be interested in

Atoms are attracted to each other because____

yaroslaw [1]

Answer:

A

Explanation:

Opposite attract. Since electrons are negative they will be attracted to the protons because they a positive

4 0

3 years ago

umka2103 [35]

Answer:

$x=2.4365\ m$

and

$x=-1.4365\ m$

Explanation:

Given:

first charge, $q_1=5\times 10^{-3}\ C$

second charge, $q_2=3\times 10^{-3}\ C$

position of first charge, $x_1=-2\ m$

position of second charge, $x_2=-1\ m$

Now since there are only 2 charges and of the same sign so they repel each other. This repulsion will be zero at some point on the line joining the charges.

<u>Now, according to the condition, electric field will be zero where the effects of field due to both the charges is equal.</u>

$E_1=E_2$

since first charge is greater than the second charge so we may get a point to the right of the second charge and the distance between the two charges is 1 meter.

$\frac{1}{4\pi.\epsilon_0} \frac{q_1}{(r+1)^2} =\frac{1}{4\pi.\epsilon_0} \frac{q_2}{(r)^2}$

$\frac{5\times 10^{-3}}{(r+1)^2} = \frac{3\times 10^{-3}}{(r)^2}$

$3(r^2+1+2r)=5r^2$

$2r^2-6r-3=0$

$r=3.4365 \&\ r=-0.4365$

Since we have assumed that the we may get a point to the right of second charge so we calculate with respect to the origin.

$x=-1+3.4365=2.4365\ m$

and

$x=-1-0.4365=-1.4365\ m$

6 0

3 years ago

What type of change accurs when a substance stays the same

Thepotemich [5.8K]

This would be a physical change because it can change back to its original form. This is like ripping paper. You can piece it back together and it still is paper.

The opposite of this is chemical change. Chemical change means the product has been changed completely like burning paper. The paper has now been turned to ash and it's impossible to change this back to its original form.

3 0

3 years ago

Gary saved dimes and nickels at a ratio of 5:7. Then, he saved 20% more dimes and 3 times the original number of nickels. If he

TiliK225 [7]

Answer:

i think 53 or 56

Explanation:

cause i cross multiplied and got that

8 0

3 years ago

Read 2 more answers

A sound that's produced by a single wave at a constant frequency and with no overtones is called

notka56 [123]

It is called a pure sound

7 0

3 years ago