Answer:
The magnitude of the lift generated by the wings of the airplane is 130,340 N.
Explanation:
Given;
mass of the airplane, m = 13,300 kg
speed of the airplane, v = 560 km/h = 155.56 m/s
The magnitude of the lift generated by the wings of the airplane is calculated as;
Therefore, the magnitude of the lift generated by the wings of the airplane is 130,340 N.
Work done is equal to the force times the distance over which that force acts (provided they are parallel vectors) In symbols we say:
Since gravity acts downward and the elevator goes upward, the dot product is reduced to a simple multiplication problem. First we need the downward force of the elevator, which is the weight according to F=ma. F=1500kg*9.81m/s^2=14715N. Then W=14715N*100m=1471500J, or 1.4715MJ
A+b(2d*5d)+7654321−2234567
<span>=<span><span>a+<span><span>10b</span><span>d^2</span></span></span>+</span></span>5419754<span>=<span><span><span>(<span><span>10b</span><span>d^2</span></span>)</span>+<span>(a)</span></span>+</span></span>5419754<span>=<span><span><span><span>10b</span><span>d^2</span></span>+a</span>+5419754
</span></span>Answer:<span>=<span><span><span><span>10b</span><span>d^2</span></span>+a</span>+5419754</span></span>
Answer:
Divergent plate margins
Explanation:
Divergent plate margins are constructive zones on the surface of the earth. They are constructive in the sense that new materials are brought to the surface from within the crust.
An example of such is the mid-altlantic ridge. Here as two plates pull apart, new melts up-wells and finds a way to get to the surface where they cool and solidify.
Answer:
The electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts
Explanation:
Electric potential is given as;
V = E*r
where;
E is the electric field strength, = kq/r²
V = ( kq/r²)*r
V = kq/r
k is coulomb's constant = 8.99 X 10⁹ Nm²/C²
q is the charge of the particles = 1.6 X 10⁻¹⁹ C
r is the distance between the particles = 859 nm
At midpoint, the distance = r/2 = 859nm/2 = 429.5 nm
V = (8.99 X 10⁹ * 1.6 X 10⁻¹⁹)/ (429.5 X 10⁻⁹)
V = 3.349 X 10⁻³ Volts
Therefore, the electric potential at the midpoint between the two particles is 3.349 X 10⁻³ Volts