1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
soldi70 [24.7K]
3 years ago
5

In 1949, an automobile manufacturing company introduced a sports car (the "Model A") which could accelerate from 0 to speed v in

a time interval of Δt. In order to boost sales, a year later they introduced a more powerful engine (the "Model B") which could accelerate the car from 0 to speed 2.92v in the same time interval. Introducing the new engine did not change the mass of the car. Compare the power of the two cars, if we assume all the energy coming from the engine appears as kinetic energy of the car.
Physics
1 answer:
Fudgin [204]3 years ago
7 0

Answer: \frac{P_B}{P_A} = 8.5264

Explanation: Power is the rate of energy transferred per unit of time: P = \frac{E}{t}

The energy from the engine is converted into kinetic energy, which is calculated as: KE = \frac{1}{2}.m.v^{2}

To compare the power of the two cars, first find the Kinetic Energy each one has:

<u>K.E. for Model A</u>

KE_A = \frac{1}{2}.m.v^{2}

<u>K.E. for model B</u>

KE_B = \frac{1}{2}.m.(2.92v)^{2}

KE_B = \frac{1}{2}.m.8.5264v^{2}

Now, determine Power for each model:

<u>Power for model A</u>

P_{A} = \frac{m.v^{2} }{2.t}

<u>Power for model B</u>

P_B = \frac{m.8.5264.v^{2} }{2.t}

Comparing power of model B to power of model A:

\frac{P_B}{P_A} = \frac{m.8.5264.v^{2} }{2.t}.\frac{2.t}{m.v^{2} }

\frac{P_B}{P_A} = 8.5264

Comparing power for each model, power for model B is 8.5264 better than model A.

<u />

You might be interested in
A total charge of 9.0 mC passes through a cross-sectional area of a nichrome wire in 3.6s. The number of electrons passing throu
Setler79 [48]
<h2>Given :</h2>

  • total charge = 9.0 mC = 0.009 C

Each electron has a charge of :

1.6 \times 10 {}^{ - 19} \:  C

For producing 1 Cuolomb charge we need :

  • \mathrm{\dfrac{1}{1.6 \times 10 {}^{ - 19} } }

  • \dfrac{10 {}^{19} }{1.6}

  • \dfrac{10\times 10 {}^{19} }{16}

  • \dfrac{100 \times 10 {}^{18} }{16}

  • \mathrm{6.24 \times 10 {}^{18}  \:  \: electrons}

Now, for producing 0.009 C of charge, the number of electrons required is :

  • 0.009 \times 6.24 \times  {10}^{18}

  • 0.05616 \times 10 {}^{18}

  • \mathrm{5.616 \times 10 {}^{16}  \:  \: electons}

_____________________________

So, Number of electrons passing through the cross section in 3.6 seconds is :

\mathrm{5.616 \times 10 {}^{16} \:  \: electrons}

Number of electrons passing through it in 1 Second is :

  • \dfrac{5.616 \times  {10}^{16} }{3.6}

  • \mathrm{1.56 \times 10 {}^{16}  \:  \: electrons}

Now, in 10 seconds the number of electrons passing through it is :

  • 10 \times  \mathrm{1.56 \times 10 {}^{16}  \:  \: }

  • \mathrm{1.56 \times 10 {}^{17}  \:  \: electrons}

_____________________________

\mathrm{ \#TeeNForeveR}

6 0
3 years ago
Your low-flow showerhead is delivering water at 1.2×10−4m3/s, about 2.0 gallons per minute.
Oksanka [162]

To solve this problem it is necessary to apply the fluid mechanics equations related to continuity, for which the proportion of the input flow is equal to the output flow, in other words:

Q_1 = Q_2

We know that the flow rate is equivalent to the velocity of the fluid in its area, that is,

Q = VA

Where

V = Velocity

A = Cross-sectional Area

Our values are given as

Q_2 = 1.2*10^{-4}m^3/s

d = 0.021m

r = \frac{0.021}{2} = 0.0105m

Since there is continuity we have now that,

V_1A_1 = Q_2

V_1A_1 = 1.2*10^{-4}

V_1 = \frac{1.2*10^{-4}}{A_2}

V_1 = \frac{1.2*10^{-4}}{\pi r^2}

V_1 = \frac{1.2*10^{-4}}{\pi (0.0105)^2}

V_1 =0.347m/s

Therefore the speed of the water's house supply line is 0.347m/s

7 0
3 years ago
How would you expect earthworms to respond to any strong chemical odor? WILL GIVE BRAINLIEST IF RIGHT!!!
Setler [38]

Answer:

<em><u>Hypothesis #2 If an earthworm is exposed to a strong odor, then it will back away from the odor because it will think that the odor is a sign of danger. ... Second, you will test earthworms' response to dry conditions by providing both a dry surface and a moist surface for the earthworms to crawl on.</u></em>

4 0
3 years ago
Read 2 more answers
an object is accelerated from a constant rate of 5.00 m/s squared what will be its speed after 8.00 seconds
Brrunno [24]

Answer: The answer to this question is velocity =40m/s

Explanation: The acceleration is the change in velocity per unit time.Thus the formula for velocity is v= at

v= 5×8

v= 40m/s

4 0
3 years ago
Suppose you need to design a parachute system to help a remote camera land safely
IgorLugansk [536]

The correct answer is hang glider.

A hang-glider cannot take off from low ground since it has no power. It needs to be launched from a high location, such a mountain or a hill. The major force acting on a hang-glider is gravity. The weight of the wing and the pilot together is this. The push that keeps the aerofoil flying through the air is produced by the weight. The hang-aerofoil glider's wing's form prevents it from falling to the ground like a stone. It results in lift. An area of low pressure is created by the aerofoil's acceleration of the air passing over the top of the wing. The air moving beneath the wing is compressed as the wing moves forward and downward. After then, the aerofoil is lifted up into the region of low pressure.

The air will gradually drop if it is still. A hang-glider descends at a speed of roughly 3.6 km/h (slow walking), or about 1 meter per second. A hang-glider needs to locate air coming up at the same rate as the glider is going down in order to maintain height. A hang-glider can fly along a cliff without losing height, for instance, if there is a light breeze coming straight from the sea, the air is being forced vertically upward by the cliff at 3.6 km/h, and the glider is flying over a vertical coastal cliff. The glider will begin to gain altitude in a stronger breeze.

Some hang-glider pilots equip their craft with tiny motors and propellers. They become microlights as a result and can now take off and climb from flat ground like a regular aircraft.

To learn more about hang-glider refer the link:

brainly.com/question/1365947

#SPJ9

4 0
1 year ago
Other questions:
  • You and your best friend are bored on a saturday afternoon and decide to measure the impulse acting on a basketball when it boun
    5·2 answers
  • Which process requires water to gain 2260 joules of energy per gram?
    6·1 answer
  • The bird is held in level flight due to the force exerted on it by the air as the bird beats its wings. What is the maximum valu
    5·1 answer
  • A series RLC circuit has a resistance of 57.61 W, a capacitance of 13.13 mF, and an inductance of 196.03 mH. The circuit is conn
    8·1 answer
  • How is lightning related to static electricity?
    9·1 answer
  • Give a specific example of a machine,and describe how its mechanical efficiency might be calculated
    13·1 answer
  • Plz help
    7·1 answer
  • Friction is defined as *
    6·1 answer
  • Help plzzzzzzz i need thissssssssss
    12·1 answer
  • Given that the radius of the moon is roughly one-quarter that of the earth, find the mass of the moon in terms of the mass of th
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!