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3 years ago

Give the approximate bond angle for a molecule with an octahedral shape.A) 109.5°B) 180°C) 120°D) 105°E) 90°

Physics

1 answer:

lbvjy [14]3 years ago

8 0

Answer:

90°

Explanation:

A molecule with an octahedral shape has a central atom bonded by six atoms or groups of atoms with no lone pairs of electron. The ideal bond angles is 90°. Examples of compounds with octahedral shape are sulfur hexafluoride SF₆ and molybdenum hexacarbonyl Mo(CO)₆

For a molecule with an octahedral shape:

Number of Electron Groups = 6

Electron-Group Geometry = octahedral

Number of Lone Pairs = 0

Valence Shell Electron Pair Repulsion (VSEPR) Notation = AX₆E₀ or AX₆

Ideal Bond Angles = 90°

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3 years ago

Chanice drives her scooter 7 kilometers north. she stops for lunch and then drives 5 kilometers and then 1 km east again. what d

lord [1]

Distance covered is given as follows

1). 7 km North

2). 5 km North

3). 1 km East

Now total distance covered will be given as

$d = d_1 + d_2 + d_3$

$d = 7 km + 5 km + 1 km$

$d = 13 km$

Now in order to find the displacement we will show all with their directions

$\vec d_1 = 7 + 5 = 12 km$ towards North

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3 years ago

What causes the sound to have a lower volume when used in a carpeted room

Viefleur [7K]

Answer:

Correct answer: The carpet material is soft, non-stick and diffuse and therefore absorbs waves.

Explanation:

The room is more acoustic if the walls and ceiling and floor are made of hard and polished material that reflects sound waves well while the carpeted room absorbs sound waves so it is less acoustic. The carpet material is soft, non-stick and diffuse and therefore absorbs waves.

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2 years ago

For a wire has a circular cross section with a radius of 1.23mm.

Mila [183]

Answer:

$5.731\times 10^{-5}\ m/s$

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Explanation:

I = Current = 3.7 A

e = Charge of electron = $1.6\times 10^{-19}\ C$

n = Conduction electron density in copper = $8.49\times 10^{28}\ electrons/m^3$

$v_d$ = Drift velocity of electrons

r = Radius = 1.23 mm

Current is given by

$I=neAv_d\\\Rightarrow v_d=\dfrac{I}{neA}\\\Rightarrow v_d=\dfrac{3.7}{8.49\times 10^{28}\times 1.6\times 10^{-19}\times \pi (1.23\times 10^{-3})^2}\\\Rightarrow v_d=5.731\times 10^{-5}\ m/s$