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cupoosta [38]
3 years ago
15

Give the approximate bond angle for a molecule with an octahedral shape.A) 109.5°B) 180°C) 120°D) 105°E) 90°

Physics
1 answer:
lbvjy [14]3 years ago
8 0

Answer:

90°

Explanation:

A molecule with an octahedral shape has a central atom bonded by six atoms or groups of atoms with no lone pairs of electron. The ideal bond angles is 90°. Examples of compounds with octahedral shape are sulfur hexafluoride SF₆ and molybdenum hexacarbonyl Mo(CO)₆

For a molecule with an octahedral shape:

Number of Electron Groups = 6

Electron-Group Geometry = octahedral

Number of Lone Pairs = 0

Valence Shell Electron Pair Repulsion  (VSEPR) Notation = AX₆E₀ or AX₆

Ideal Bond Angles = 90°

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The part of the electromagnetic spectrum has a shorter wavelength than ultraviolet light is x-rays.
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3 years ago
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A sled slides down a hill with friction between the sled and hill but negligible alr resistance. Which of the following must be
Andreyy89

Answer:

A) The sum of the kinetic energy and the gravitational potential energy changes by an amount equal to the energy dissipated by friction,

Explanation:

  • The kinetic energy is the energy that the object has and is defied by the work that is needed to accelerate the body.
  • The gravitational potential is a mechanism by which an equal amount of energy is being transferred per unit mass that is needed for the object to move from the specific location.
  • Hence when the sled moves down the hill with the force of gravity it has negligible resistance as an equal amount of energy is dissipated.
8 0
3 years ago
In 1923, the United States Army (there was no U.S. Air Force at that time) set a record for in-flight refueling of airplanes. Us
dybincka [34]

Answer:

1.95m/s

Explanation:

Please view the attached file for the detailed solution.

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6 0
3 years ago
The weight of a hydraulic barber's chair with a client is 2100 N. When the barber steps on the input piston with a force of 44 N
guajiro [1.7K]

Answer:

\frac{r_1}{r_2}=6.9

Explanation:

According to Pascal's Law, the pressure transmitted from input pedal to the output plunger must be same:

P_1 = P_2\\\\\frac{F_1}{A_1}=\frac{F_2}{A_2}\\\\\frac{F_1}{F_2}=\frac{A_1}{A_2}\\\\\frac{F_1}{F_2}=\frac{\pi r_1^2}{\pi r_2^2}\\\\\frac{F_1}{F_2}=\frac{r_1^2}{r_2^2}

where,

F₁ = Load lifted by output plunger = 2100 N

F₂ = Force applied on input piston = 44 N

r₁ = radius of output plunger

r₂ = radius of input piston

Therefore,

\frac{r_1^2}{r_2^2}=\frac{2100\ N}{44\ N}\\\\\frac{r_1}{r_2}=\sqrt{\frac{2100\ N}{44\ N}} \\\\\frac{r_1}{r_2}=6.9

4 0
3 years ago
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Fynjy0 [20]

Answer:

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