All categories

3 years ago

Give the approximate bond angle for a molecule with an octahedral shape.A) 109.5°B) 180°C) 120°D) 105°E) 90°

Physics

1 answer:

lbvjy [14]3 years ago

8 0

Answer:

90°

Explanation:

A molecule with an octahedral shape has a central atom bonded by six atoms or groups of atoms with no lone pairs of electron. The ideal bond angles is 90°. Examples of compounds with octahedral shape are sulfur hexafluoride SF₆ and molybdenum hexacarbonyl Mo(CO)₆

For a molecule with an octahedral shape:

Number of Electron Groups = 6

Electron-Group Geometry = octahedral

Number of Lone Pairs = 0

Valence Shell Electron Pair Repulsion (VSEPR) Notation = AX₆E₀ or AX₆

Ideal Bond Angles = 90°

You might be interested in

A lighthouse is located on a small island, 3 km away from the nearest point on a straight shoreline, and its light makes four re

lbvjy [14]

Answer:

The beam of light is moving at the peed of:

$\frac{dy}{dt} = \frac{80\pi}{3}$ km/min

Given:

Distance from the isalnd, d = 3 km

No. of revolutions per minute, n = 4

Solution:

Angular velocity, $\omega = \frac{d\theta'}{dt} = 2\pi n = 2\pi \times 4 = 8\pi$ (1)

Now, in the right angle in the given fig.:

$tan\theta' = \frac{y}{3}$

Now, differentiating both the sides w.r.t t:

$\frac{dtan\theta'}{dt} = \frac{dy}{3dt}$

Applying chain rule:

$\frac{dtan\theta'}{d\theta'}.\frac{d\theta'}{dt} = \frac{dy}{3dt}$

$sec^{2}\theta'\frac{d\theta'}{dt} = \frac{dy}{3dt} = (1 + tan^{2}\theta')\frac{d\theta'}{dt}$

Now, using $tan\theta = \frac{1}{m}$ and y = 1 in the above eqn, we get:

$(1 + (\frac{1}{3})^{2})\frac{d\theta'}{dt} = \frac{dy}{3dt}$

Also, using eqn (1),

$8\pi\frac{10}{9})\theta' = \frac{dy}{3dt}$

$\frac{dy}{dt} = \frac{80\pi}{3}$

7 0

2 years ago

Which phrase does not describe a mineral?

Jobisdone [24]

The answer is A) specific chemical consumption

3 0

2 years ago

Read 2 more answers

In a sun's life span, if the Hydrogen to Helium ratio at the Red Giant phase is 100% Helium and 0% Hydrogen, Predict the Hydroge

serg [7]

Answer:

3rd bc the atmoce

Explanation:

4 0

2 years ago

Which of the following are features of the nucleus of an atom

vichka [17]

We r made of atom so v can’t touch anything hehe I just joking

4 0

2 years ago

The nucleus of the polonium isotope 214 Po (mass 214 u) is radioactive and decays by emitting an alpha particle (a helium nucleu

amid [387]

Answer:

368224.29906 m/s

Explanation:

M = Mass of Polonium nucleus = 214 u

V = Velocity of nucleus

m = Mass of Helium nucleus = 4 u

v = Velocity of alpha particle = $1.97\times 10^7\ m/s$

In this system the momentum is conserved

$MV+mv=0\\\Rightarrow MV=-mv\\\Rightarrow 214V=-4\times 1.97\times 10^7\\\Rightarrow V=\dfrac{-4\times 1.97\times 10^7}{214}\\\Rightarrow V=368224.29906\ m/s$

The recoil speed of the nucleus that remains after the decay is 368224.29906 m/s

6 0

2 years ago

Read 2 more answers