Given:
A circle with diameter 9 cm.
To find:
The area of the circle.
Solution:
The area of a circle is:
...(i)
Where r is the radius.
We know that, the diameter of a circle is twice than its radius.
The diameter of the given circle is 9 cm.
Substituting 
in (i), we get
Therefore, the area of the given circle is 63.6.
Answer:
Minimum = 10
Q1 (quartile 1) = 14.5
Medium = 16
Q3 (quartile 3) = 17
Maximum = 18
Step-by-step explanation:
You just arrange the numbers in from smallest to greatest (even if some of them repeat). Then, look for the maximum and minimum. Get the median by having the same numbers left from both sides until reaching the median. The same holds for the quartiles (if you have for example two numbers for the quartile, as in this case 14 and 15, add the up and divide them by 2, in this case 14.5.
Tell me if I'm correct please
Answer:
D
Step-by-step explanation:
Under a counterclockwise rotation about the origin of 90°
a point (x, y) → (- y, x)
A translation of 3 units up → + 3 in the y- direction, that is add 3 to the y- coordinate, hence
(x, y) → (- y, x) → (- y, x+ 3) → D
To convert fractions to decimals, divide the denominator into the numerator
3/9= .333333
123/999=.123123
hope this helps
