1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Free_Kalibri [48]
3 years ago
12

What mass of powdered drink mix is needed to make a 0.5 M solution of 100 mL?

Chemistry
2 answers:
son4ous [18]3 years ago
8 0

<u>Answer:</u> The mass of powdered drink mix is 17.1 grams.

<u>Explanation:</u>

The powdered drink mix has sucrose compound in it. So, we need to calculate the mass of sucrose in the given molar solution.

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of sucrose}\times \text{Volume of solution (in mL)}}

Molarity of solution = 0.5 M

Volume of solution = 100 mL

Molar mass of sucrose = 342.3 g/mol

Putting values in above equation, we get:

0.5M=\frac{\text{Mass of sucrose}\times 1000}{342.3g/mol\times 100mL}\\\\\text{Moles of sucrose}=\frac{0.5\times 342.3\times 100}{1000}=17.1g

Hence, the mass of powdered drink mix is 17.1 grams.

Maru [420]3 years ago
3 0

Answer:

There is 17,114825 g of powdered drink mix needed

Explanation:

<u>Step 1 :</u> Calculate moles

As given, the concentration of the drink is 0.5 M, this means 0.5 mol / L

Since the volume is 100mL, we have to convert the concentration,

⇒0.5 / 1   =  x /0.1    ⇒ 0.5* 0.1  = x = 0.05 M

This means there is 0.05 mol per 100mL

e

<u>Step 2 </u>: calculate mass of the powdered drink

here we use the formula n (mole) = m(mass) / M (Molar mass)

⇒ since powdered drink mix is usually made of sucrose (C12H22O11) and has a molar mass of 342.2965 g/mol.

0.05 mol = mass / 342.2965 g/mol

To find the mass, we isolate it ⇒0.05 mol * 342.2965 g/mol = 17,114825g

There is 17,114825 g of powdered drink mix needed

You might be interested in
Gallium has two naturally occurring isotopes with the following masses and natural abundances: Isotope Mass ( amu ) Abundance (%
ICE Princess25 [194]
The formula for determination of atomic mass given the mass of isotopes and relative abundance is:

Ar = ∑(mass * abundance) / 100
Ar = (68.92558 * 60.108 + 70.92470 * 39.892) / 100
Ar = 69.72306

The atomic mass of gallium is 69.72306 amu
4 0
3 years ago
A number of substances and their chemical formulas are listed below. Check the ones that are compounds. neon (Ne) carbon monoxid
Oxana [17]

Answer:

carbon monoxide (CO)

glucose (C6H12O6)

Explanation:

4 0
3 years ago
A chemist designs a galvanic cell that uses these two half-reactions: half-reaction standard reduction potential (s)(aq)(aq)(l)
miv72 [106K]

Answer:

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)  

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻        

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

E°cell = 1.10 V

Explanation:

<em>The half-reactions are missing, but I will propose some to show you the general procedure and then you can apply it to your equations.</em>

<em>Suppose we have the following half-reactions.</em>

<em>Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)   E°red = 0.34 V</em>

<em>Zn²⁺(⁺aq) + 2 e⁻ → Zn(s)    E°red = -0.76 V</em>

<em />

To identify how to make a spontaneous cell, we need to consider the standard reduction potentials (E°red). The half-reaction with the higher E°red will occur as a reduction (in the cathode), whereas the one with the lower E°red will occur as an oxidation (in the anode).

Reduction (cathode): Cu²⁺(⁺aq) + 2 e⁻ → Cu(s)   E°red = 0.34 V

Oxidation (anode): Zn(s) → Zn²⁺(⁺aq) + 2 e⁻        E°red = -0.76 V

To get the overall equation we add both half-reactions.

Cu²⁺(⁺aq) + Zn(s) → Cu(s) + Zn²⁺(⁺aq)

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

E°cell = 0.34 V - (-0.76 V) = 1.10 V

Since E°cell > 0, the reaction is spontaneous.

5 0
3 years ago
How many liters of N2 gas is needed to produce 500 L NH3?
Veseljchak [2.6K]
I think the answer is 101.2 L
6 0
3 years ago
What factors affect the dynamic state of equilibrium in a chemical reaction and how?
yanalaym [24]

Answer:

Only changes in temperature will influence the equilibrium constant K_c. The system will shift in response to certain external shocks. At the new equilibrium Q will still be equal to K_c, but the final concentrations will be different.

The question is asking for sources of the shocks that will influence the value of Q. For most reversible reactions:

  • External changes in the relative concentration of the products and reactants.

For some reversible reactions that involve gases:

  • Changes in pressure due to volume changes.

Catalysts do not influence the value of Q. See explanation.

Explanation:

\displaystyle K_c = {e}^{\Delta G/(R\cdot T)}.

Similar to the rate constant, the equilibrium constant K_c depends only on:

  • \Delta G the standard Gibbs energy change of the reaction, and
  • T the absolute temperature (in degrees Kelvins.)

The reversible reaction is in a dynamic equilibrium when the rate of the forward reaction is equal to the rate of the backward reaction. Reactants are constantly converted to products; products are constantly converted back to reactants. However, at equilibrium Q = K_c the two processes balance each other. The concentration of each species will stay the same.

Factors that alter the rate of one reaction more than the other will disrupt the equilibrium. These factors shall change the rate of successful collisions and hence the reaction rate.

  • Changes in concentration influence the number of particles per unit space.
  • Changes in temperature influence both the rate of collision and the percentage of particles with sufficient energy of reaction.

For reactions that involve gases,

  • Changing the volume of the container will change the concentration of gases and change the reaction rate.

However, there are cases where the number of gases particles on the reactant side and the product side are equal. Rates of the forward and backward reaction will change by the same extent. In such cases, there will not be a change in the final concentrations. Similarly, catalysts change the two rates by the same extent and will not change the final concentrations. Adding noble gases will also change the pressure. However, concentrations stay the same and the equilibrium position will not change.

8 0
3 years ago
Other questions:
  • Help I have no idea what I'm doing!!
    13·2 answers
  • In the equation c2h4 + 3o2 = ? co2 + 2h2o, how many co2 molecules are needed to balance the equation?
    7·1 answer
  • The main reasons why ch4 has a higher vapor pressure at a given temperature when compared to ch3cl is that ch4 and . 2. the main
    9·1 answer
  • The pressure of gas is affected by the number of particles and is not affected by the kind of gas in the container. What does th
    13·1 answer
  • write a balanced equation for the reaction between hydrogen peroxide H202 and Fe2+ to produce Fe3+ and H2O in acidic solution​
    15·1 answer
  • Identify the compound with the highest percent ionic character. identify the compound with the highest percent ionic character.
    11·1 answer
  • What type of reaction is Mg + H2Cl2 — MgCl2 + H2?
    14·1 answer
  • Un aerosol contine 350 ml de gas en su interior . Su presion es de 5 atm. Un estudiante coloca un arosol en una bolsa plastica y
    14·1 answer
  • What is the chemical name of the compound K2SO4? Use the list of polyatomic ions and the periodic table to help you answer.
    10·2 answers
  • Multiple Select Question
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!