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nadya68 [22]
2 years ago
15

3. The diet of white-tailed deer consists primarily of shrubs. Sika are

Chemistry
1 answer:
olga_2 [115]2 years ago
3 0
Sika have more food choices because they eat both grasses and shrubs, compared to the white-tailed dear who only eats shrubs.
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Multiple choice
mihalych1998 [28]

Answer:

S + 4 Cl2

Explanation:

Sulphur - S

1 mol of Sulphur = S

Chlorine = Cl2

4 moles of Chlorine = 4Cl2

4S + 2Cl2

Incorrect option

S + 4 Cl2

Correct option

S + 2Cl2

Incorrect option

S + Cl2

Incorrect option

7 0
3 years ago
Round the following number to four significant figures and express the result in standard exponential notation: 442,722 *
OleMash [197]

Answer:

4.427 × 10⁵

Explanation:

In mathematics, rounding up a number is a way to get a more simpler figure but not too distant from the original number. Rounding up a whole number like this (442722) to significant figures means having only four non-zero digits in the figure i.e. 442722 ~ 442700.

This means that 442722 has been rounded up to 4s.f. Hence, to use scientific notations to represent our answer, we count the number of decimal places from right to left i.e.

442700 = 5 decimal places if the point is between 4 and 4 i.e. 4.427

Therefore, the figure 442700 can be written as 4.427 × 10⁵ using scientific notation.

5 0
3 years ago
What variables are used to calculate speed
Oksanka [162]

S /\ Speed

mph, km/h, ft/s

6 0
3 years ago
Read 2 more answers
How do solute concentrations affect the rate of osmosis within the cell?
igor_vitrenko [27]

Answer:

Image result for How do solute concentrations affect the rate of osmosis within the cell?

Concentration gradient - The movement of osmosis is affected by the concentration gradient; the lower the concentration of the solute within a solvent, the faster osmosis will occur in that solvent.

I think this is it^^^

Explanation:

7 0
3 years ago
HELP ASAP!!! 2C4H10(g) + 1302 ===> 8CO2(g) + 10H2O(g)
Ivan

Answer:

30.34g (corrected to 4 significant figures).

Explanation:

Take the atomic mass of C=12.0, H=1.0, O=16.0.

no. of moles = mass / molar mass

So, no. of moles of butane reacted = 10 / (12x4 + 1x10)

= 0.172414 mol

Since O2 is in excess and butane is the limiting reagent, the no. of moles of carbon dioxide produced depends on the no. of moles of butane reacted.

From the equation, the mole ratio of butane:Carbon dioxide = 2: 8 = 1: 4,

meaning 1 mole of butane gives 4 moles of CO2.

Using this ratio,

we can deduce that the no. of moles of CO2 produced =  0.172414 x 4

=0.689655 mol

As mass = no. of moles x molar mass

mass of CO2 produced =   0.689655 x (12.0+16.0x2)

=30.34g (corrected to 4 significant figures).

6 0
3 years ago
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