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Shtirlitz [24]
3 years ago
5

A scientist has 0.12 miles of a gas at a pressure of 4.06 kPa and a volume of 14 liters in an enclosed container. What is the te

mperature of the gas in the container?
Chemistry
1 answer:
natka813 [3]3 years ago
7 0

Answer:

56972.17K

Explanation:

P = 4.06kPa = 4.06×10³Pa

V = 14L

n = 0.12 moles

R = 8.314J/Mol.K

T = ?

We need ideal gas equation to solve this question

From ideal gas equation,

PV = nRT

P = pressure of the ideal gas

V = volume the gas occupies

n = number of moles

R = ideal gas constant

T = temperature of the gas

PV = nRT

T = PV / nR

T = (4.06×10³ × 14) / (0.12 × 8.314)

T = 56840 / 0.99768

T = 56972.17K

Note : we have a large number for temperature because we converted the value of pressure from kPa to Pa

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Explanation:

It is known that relation between wavelength and frequency is as follows.

                  \lambda = \frac{c}{\nu}

where,        \lambda = wavelength

                       c = speed of light = 3 \times 10^{8} m/s

                  [/tex]\nu[/tex] = frequency

It is given that frequency is 7.2 \times 10^{11} s^{-1}. Hence, putting this value into the above formula and calculate the wavelength as follows.

                    \lambda = \frac{c}{\nu}

                    \lambda = \frac{3 \times 10^{8} m/s}{7.2 \times 10^{11} s^{-1}}

                             = 0.416 \times 10^{-3} m

or,                         = 4.16 \times 10^{-4} m

Thus, we can conclude that wavelength of given radiation is 4.16 \times 10^{-4} m.

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Answer:

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Explanation:

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True is the answer to this question

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