Answer:
The oxidizing agent is the MnO₄⁻
Explanation:
This is the redox reaction:
10 I⁻ (aq) + 2 MnO₄⁻ (aq) + 16 H⁺ (aq) → 5 I₂ (s) + 2 Mn²⁺ (aq) + 8 H2O (l)
Let's determine the oxidation and the reduction.
I⁻ acts with -1 in oxidation state and changes to 0, at I₂.
All elements in ground state has 0 as oxidation state.
As the oxidation state has increased, this is the oxidation, so the iodide is the reducing agent.
In the permanganate (MnO₄⁻), Mn acts with +7 in oxidation state and decreased to Mn²⁺. As the oxidation state is lower, we talk about the reduction. Therefore, the permanganate is the oxidizing agent because it oxidizes iodide to iodine
c. 1.5 moles of Cu will contain a total of 9.0 * 10 ^ 23 atoms.
Explanation:
To convert moles into atoms, the molar amount and number of atom is multiplied by Avagadro's number.
Avagadro's number is 6.022×
So applying the formula in the given sample:
A) 0.5×6.022×
3.01×
atoms.
B) 0.75 mole of H20
O.75×6.022×
= 4.5166×
atoms.
C) 1.5 moles of Cu
1.5×6.022×
= 9.033×
D). 1.5 moles of H2
1.5 × 2 × 6.022 × 
= 18.066 ×
atoms because H2 is 2 moles of hydrogen.
Atom is the smallest entity of matter having property of the element to which it is a part.
Using AVOs number
moles -> molecules
multiply moles # by AVOs #
15 x (6.022x10^23=
I believe it is a decomposition