<span>They lower the activation energy.</span>
Answer:
ΔG = -61.5 kJ/mol (<u>Spontaneous process</u>)
Explanation:
2 NO (g) + O₂ (g) ⇄ 2NO₂ (g)
Let's apply the thermodynamic formula to calculate the ΔG
ΔG = ΔG° + R .T . lnQ
We don't know if the gases are at equilibrium, that's why we apply Q (reaction quotient)
ΔG = - 69 kJ/mol + 8.31x10⁻³ kJ/K.mol . 298K . ln Q
How can we know Q? By the partial pressures (Qp)
P NO = 0.450atm
PO₂ = 0.1 atm
PNO₂ = 0.650 atm
Qp = [NO₂]² / [NO]² . [O₂]
Qp = 0.650² / 0.450² . 0.1 = 20.86
ΔG = - 69 kJ/mol + 8.31x10⁻³ kJ/K.mol . 298K . ln 20.86
ΔG = -61.5 kJ/mol (<u>Spontaneous process</u>)
H. using a pulley system can reduce the load force, over a greater distance.<span />
The answer is 67.82 g/mol
Molar mass C6H12O6 = 12 x 6 + 1 x 12 + 16 x 6 = 180 g/mol
1 mole ------------ 180 g
( moles ) --------- 843.211 g
moles = 843.211 x 1 / 180
moles = 843.211 / 180
= 4,684 moles of C6H12O6
