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makkiz [27]
2 years ago
15

On an artificial reef in the Mediterranean Sea, the rocky bottom, the Dover sole, and the

Chemistry
1 answer:
natka813 [3]2 years ago
7 0

Taking into account the animals and the landscape being mentioned, we can confirm that the combination of these forms<u><em> part of an </em></u><u><em>ecosystem</em></u><u><em>.</em></u>

An ecosystem is described as an area consisting of:

  • Plants
  • Animals
  • Bacteria
  • Weather
  • Landscape

and many other factors, which all work together to form a small pocket of life.

Ecosystems are described as containing both living and non-living elements, meaning biotic and non-biotic parts. A community or population, on the other hand, <u>are used to consider only the </u><u>biotic </u><u>or </u><u>living factors </u><u>of an </u><u>ecosystem</u><u>. </u>Therefore, since the question includes the rock bottom (a<em><u> non-biotic factor</u></em>) as a part of the makeup, the only correct grouping is that of an ecosystem.

To learn more visit:

brainly.com/question/13952438?referrer=searchResults

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How many moles are in 8.63 x 103 atoms of Li?
Ira Lisetskai [31]
<h3>Answer:</h3>

1.43 × 10⁻²⁰ mol Li

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>Explanation:</h3>

<u>Step 1: Define</u>

8.63 × 10³ atoms Li

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                              \displaystyle 8.63 \cdot 10^3 \ atoms \ Li(\frac{1 \ mol \ Li}{6.022 \cdot 10^{23} \ atoms \ Li})
  2. Multiply/Divide:                \displaystyle 1.43355 \cdot 10^{-20} \ moles \ Li

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.43355 × 10⁻²⁰ mol Li ≈ 1.43 × 10⁻²⁰ mol Li

4 0
2 years ago
Part A
Roman55 [17]

These are two questions and two answers

Question 1.

Answer:

  • <u>7.33 × 10 ⁻³ c</u>

Explanation:

<u>1) Data:</u>

a) m = 9.11 × 10⁻³¹ kg

b) λ =  3.31 × 10⁻¹⁰ m

c) c = 3.00 10⁸ m/s

d) s = ?

<u>2) Formula:</u>

The wavelength (λ), the speed (s), and the mass (m) of the particles are reltated by the Einstein-Planck's equation:

  • λ = h / (m.s)

  • h is Planck's constant: h= 6.626×10⁻³⁴J.s

<u>3) Solution:</u>

Solve for s:

  • s = h / (m.λ)

Substitute:

  • s = 6.626×10⁻³⁴J.s / ( 9.11 × 10⁻³¹ kg ×  3.31 × 10⁻¹⁰ m) = 2.20 × 10 ⁶ m/s

To express the speed relative to the speed of light, divide by c =  3.00 10⁸ m/s

  • s =  2.20 × 10 ⁶ m/s / 3.00 10⁸ m/s = 7.33 × 10 ⁻³

Answer: s = 7.33 × 10 ⁻³ c

Question 2.

Answer:

  • 2.06 × 10 ⁻³⁴ m.

Explanation:

<u>1) Data:</u>

a) m = 45.9 g (0.0459 kg)

b) s = 70.0 m/s

b) λ =  ?

<u>2) Formula:</u>

Macroscopic matter follows the same Einstein-Planck's equation, but the wavelength is so small that cannot be detected:

  • λ = h / (m.s)

  • h is Planck's constant: h= 6.626×10⁻³⁴J.s

<u>3) Solution:</u>

  • λ = h / (m.s)

Substitute:

  • λ =  6.626×10⁻³⁴J.s / ( 0.0459 kg ×  70.0 m/s) = 2.06 × 10 ⁻³⁴ m

As you see, that is tiny number and explains why the wave nature of the golf ball is undetectable.

Answer: 2.06 × 10 ⁻³⁴ m.  

5 0
2 years ago
In the unbalanced equation given below, what is the element that is gaining electrons?
viktelen [127]

Hey there!:

HCl + MnO2 → MnCl2 + H2O + Cl2

* in HCl the oxidation state of Cl is -1 .

* on the product side the oxidation state is 0 .

* therefore Cl gains electrons .

* in  MnO2 the oxidation state of Mn is +4

* in MnCl2 the oxidation state of Mn is +2

Therefore Mn loses electrons

Answer A

Hope That helps!

4 0
2 years ago
Read 2 more answers
What are 4 similarities of Metals, Nonmetals, and Metalloids?
igor_vitrenko [27]
The answer is           


e o i and a



not really sure forgive me if im wrong


7 0
3 years ago
Consider the reaction below. NH4+ + H2O mc013-1.jpg NH3 + H3O+ Which is an acid-conjugate base pair? NH4+ and NH3 NH4+ and H3O+
juin [17]
NH4+ and NH3 are an acid-conjugate base pair, since NH4+ is an acid, while NH3 is its conjugate base (since it is without the H+).
H2O and H3O+ can also be considered an acid-conjugate base pair, since H3O+ is an acid, while H2O would be its conjugate base. (But if only 1 answer is to be selected, it should be the NH4+ and NH3)
NH4+ and H3O+ are both acids, and both H2O and NH3 can be considered bases.
4 0
3 years ago
Read 2 more answers
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