I can’t see the picture for some reason but if I were to guess, I would say Pangea.
Answer:
The rate at which ammonia is being produced is 0.41 kg/sec.
Explanation:
Haber reaction
Volume of dinitrogen consumed in a second = 505 L
Temperature at which reaction is carried out,T= 172°C = 445.15 K
Pressure at which reaction is carried out, P = 0.88 atm
Let the moles of dinitrogen be n.
Using an Ideal gas equation:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
![n=\frac{PV}{RT}=\frac{0.88 atm\times 505 L}{0.0821 atm l/mol K\times 445.15 K}=12.1597 mol](https://tex.z-dn.net/?f=n%3D%5Cfrac%7BPV%7D%7BRT%7D%3D%5Cfrac%7B0.88%20atm%5Ctimes%20505%20L%7D%7B0.0821%20atm%20l%2Fmol%20K%5Ctimes%20445.15%20K%7D%3D12.1597%20mol)
According to reaction , 1 mol of ditnitrogen gas produces 2 moles of ammonia.
Then 12.1597 mol of dinitrogen will produce :
of ammonia
Mass of 24.3194 moles of ammonia =24.3194 mol × 17 g/mol
=413.43 g=0.41343 kg ≈ 0.41 kg
505 L of dinitrogen are consumed in 1 second to produce 0.41 kg of ammonia in 1 second. So the rate at which ammonia is being produced is 0.41 kg/sec.
Helium only possesses two valence electrons, while the other noble gasses posses eight
<h3><u>Answer</u>;</h3>
= 226 Liters of oxygen
<h3><u>Explanation</u>;</h3>
We use the equation;
LiClO4 (s) → 2O2 (g) + LiCl, to get the moles of oxygen;
Moles of LiClO4;
(500 g LiClO4) / (106.3916 g LiClO4/mol)
= 4.6996 moles
Moles of oxygen;
But, for every 1 mol LiClO4, two moles of O2 are produced;
= 9.3992 moles of Oxygen
V = nRT / P
= (9.3992 mol) x (8.3144621 L kPa/K mol) x (21 + 273) K / (101.5 kPa)
= 226 L of oxygen
Answer:
The length of a side of the square is 4.53 cm
Explanation:
Volume (V) = mass/density
mass = 3.4 mg = 3.4/1000 = 0.0034 g
density = 19.3 g/cm^3
V = 0.0034/19.3 = 1.76×10^-4 cm^3
Volume = area × thickness
Area = volume/thickness = 1.76×10^-4/8.6×10^-6 = 20.48 cm^2
Length of one side of the square = sqrt(area of square) = sqrt(20.48 cm^2) = 4.53 cm