The volume of the textbook calculated by the student written to 3 significant figures is 992cm³
- According to this question, a student calculates the volume of his textbook and arrived at an answer of 991.880 cm³.
- To round up this digit to 3 significant figures, which means that only 3 significant numbers should appear in the answer.
- To do this, the number after the third number is 8, which means we can round up the value of 1 to 2. Hence, the volume of the textbook calculated by the student is 992cm³ in 3 s.f.
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The answer to this question is 2 and 3
The answer is; liquid phase
The characteristics described in the question are those of a liquid. The forces between liquid particles are weaker than the forces between solid particles because the particles are further apart. The particles are not held in a fixed position in the structure hence it can flow and take the shape of the container in which it is in.
Glucose has empirical formula C6H12O6. So its formula mass can be calculated from that: 12.01x6 + 1.008x12 + 16.00x6 = 72.06 + 12.096 + 96.00 = 180.156 which needs to be rounded to two decimals to get 180.16 g/mole<span>.</span>
Answer:
The correct answer is Glycolysis.
Explanation:
Glycolysis is a catabolic process that deals with the breakdown of glucose by 10 enzyme catalyzed steps to generate the end product pyruvate.
Glycolysis take place in the cytosol of an eukaryotic cell because the concentration of glucose and enzymes that catalyzes the break down of glucose remain significantly high in the cytosol.
