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Thepotemich [5.8K]
3 years ago
7

How many grams is needed to make the following solution?

Chemistry
1 answer:
Lisa [10]3 years ago
3 0

Answer:

c

Explanation:

yxyyyxyxxyxxy yy y gg ff ff d d f t r rr rr rr rr r r t tt t

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A special layer of dermal cells are found on the top side of leaves. What level of organization would it belong to
Dmitry [639]

Answer:

Tissue level of organization

Explanation:

The various levels of the organization of life are as follows:

Cells: a cell is the basic unit of ife

Tissues; A tissue is a group of cells with a common origin. performing similar functions.

Organ: an organ is a group of tissues with varied or similar function that work together to perform a specific function.

System: a system is a group of different organs that work together in the body to perform a specific function.

Since, the leaf is an organ in the plant that performs the function of photosynthesis, the group of dermal cells found on the leaf are in the tissue level of organization, they perform the function of protection for the leaf.

5 0
3 years ago
if element X has two valence electrons and element Y has five valence electrons the formula for the compound is?
malfutka [58]

Answer:

the answer to the question is X3Y2

7 0
2 years ago
What’s the solution?
emmasim [6.3K]

Answer:

See balanced equations below

Explanation:

1. Mg(s) +2 HCL (aq) →MgCl₂ (aq) +H₂(g)

This is a single replacement reaction, involving an acid with a metal

2. 2Al(s) + 3H₂SO₄ (aq)→Al₂(SO₄)₃(aq) + 3H₂

3. 3 Zn (s) + 2H₃PO₄(aq)→ Zn₃(PO₄)₂ (aq) + 3H₂ (g)

4. 2Al(s) + 6HCL (aq)→2AlCl₃(aq) +3H₂ (g)

B.

1. 2KOH(aq) + MgCl₂→Mg(OH)₂ (aq) + 2KCl (aq)

2. 3NaOH (aq)+ Al(NO₃)₃ (aq)→Al(OH)₃(s) + 3 NaNO₃(aq) ---this is a precipitation reaction

3. BaBr₂(aq) + H₂SO₄→BaSO₄ (s) + 2Br⁻(aq)

4. Na₂S + 2HCl → 2NaCl (aq) + H₂S (g)

5. 3CaCl₂ +2K₃PO₄→ Ca₃(PO₄)₂+6KCl

6.Ba(NO₃)₂ + (NH₄)₂CO₃→ 2(NH₄)⁺(aq) +BaCO₃(s)

6 0
3 years ago
. How much energy is lost by a 30.0g sample of water that decreases in temperature from 56.7C to 25.0C?
lbvjy [14]

Answer:

Q = -3980.9 j

Explanation:

Given data:

Mass of sample = 30 g

Initial temperature = 56.7 °C

Final temperature = 25 °C

Specific heat of water = 4.186 j/g.°C

Amount of heat released = ?

Formula:

Q = m.c.ΔT

Q = heat released

m = mass of sample

c = specific heat of given sample

ΔT = change in temperature

Solution:

ΔT = T2 -T1

ΔT = 25 °C - 56.7 °C = - 31.7°C

Q = m.c.ΔT

Q = 30 g × 4.186 j/g.°C ×  - 31.7°C

Q = -3980.9 j

8 0
3 years ago
Which animal is a secondary consumer in the temperate coniferous forest?
love history [14]
I positive that the answer is wolf hope that helps
4 0
3 years ago
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