How many grams is needed to make the following solution?
1 answer:
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There are several various of expressing concentration. For instance, mass percent, volume percent, Molarity, Normality, Molality, etc.
In present case, weight of solute and solvent are given, so it will be convenient to express concentration in terms of mass percent.
Given: weight of solute (Ca2+) = 8500 g
weight of solvent (water) = 490 g.
Therefore, mass of solution = 8500 + 490 = 8990 g
Now, mass percent =
=
= 94.55 %
Answer: Concentration of calcium ions is in this solution is 94.55 % (w/W)
In present case, weight of solute and solvent are given, so it will be convenient to express concentration in terms of mass percent.
Given: weight of solute (Ca2+) = 8500 g
weight of solvent (water) = 490 g.
Therefore, mass of solution = 8500 + 490 = 8990 g
Now, mass percent =
=
= 94.55 %
Answer: Concentration of calcium ions is in this solution is 94.55 % (w/W)
Answer:
34.6g
Explanation:
Given parameters:
Mass of Octane = 11.2g
Reaction expression;
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
Mass of octane = 11.2g
Unknown:
Mass of carbon dioxide produced = ?
Solution:
From the balanced reaction equation;
2 mole of octane produced 16 moles of carbon dioxide
From the given specie, let us find the number of moles;
Number of moles =
Molar mass of C₈H₁₈ = 8(12) + 18(1) = 114g/mole
Number of moles of octane = = 0.098mole
2 mole of octane produced 16 moles of carbon dioxide
0.098 mole of octane will produce = 0.79mole of CO₂
Mass of CO₂ = number of moles x molar mass
Molar mass of CO₂ = 12 + 2(16) = 44g/mol
Mass of CO₂ = 0.79 x 44 = 34.6g