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3 years ago

1.5x+0.5y=12 solve for y

Mathematics

1 answer:

Schach [20]3 years ago

8 0

Y=-3x+24

Hope this helps :)

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A dilation is a nonrigid transformation that can produce enlarged or reduced images from a given pre-image. How do you know that

Marat540 [252]

A dilation can elongate or diminish a figure. It can create an image the same as the original by using a scale factor. The scale factor of a dilation is the ratio of corresponding side lengths. To dilate a polygon, multiply the coordinates of each vertex by the scale factor k and connect the vertices.

4 0

3 years ago

Read 2 more answers

What’s the perimeter of a rectangle with length x and width x-5

MrMuchimi

Answer:

$P = 2(x + x - 5) = 2x - 10$

Step-by-step explanation:

Formula for the perimeter of a rectangle: $P = 3(l + L)$

7 0

3 years ago

what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube

Dmitrij [34]

Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

$\frac{99}{2} (2x+98)=p^3 \\ \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}$

By substitution, we have that $p=33$ and $x=314$ .

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>

3 0

3 years ago

A right square pyramid with base edges of length $8\sqrt{2}$ units each and slant edges of length 10 units each is cut by a plan

seropon [69]

Answer:

32 $unit^{3}$

Step-by-step explanation:

Given:

The slant length 10 units
A right square pyramid with base edges of length 8 $\sqrt{2}$

Now we use Pythagoras to get the slant height in the middle of each triangle:

$\sqrt{10^{2 - (4\sqrt{2} ^{2} }) }$ = $\sqrt{100 - 32}$ = $\sqrt{68}$ units

One again, you can use Pythagoras again to get the perpendicular height of the entire pyramid.

$\sqrt{68-(4\sqrt{2} ^{2} )}$ = $\sqrt{68 - 32}$ = 6 units.

Because slant edges of length 10 units each is cut by a plane that is parallel to its base and 3 units above its base. So we have the other dementions of the small right square pyramid:

The height 3 units
A right square pyramid with base edges of length 4 $\sqrt{2}$

So the volume of it is:

V = 1/3 *3* 4 $\sqrt{2}$

= 32 $unit^{3}$

5 0

4 years ago

PLZ HELP!!

svet-max [94.6K]

Answer: D

i would go with D i am not 100% sure math is not my strongest point

Hope this helps!

Step-by-step explanation:

-MalStar

4 0

3 years ago