Speed = distance/time
=> speed = 817/19 m/sec = 43 m/sec
hope it helps!
Albert Einstein's work focused on relativity theory and the as it could be applied to gravity, quantum mechanics and the theory of light.
<h3>Who is Albert Einstein?</h3>
The physicist Albert Einstein was born in Ulm Württemberg Germany in 1875. He migrated to the United States at the height of the Nazi regime in Germany where he became a professor of physics at Princeton University.
His work focused on the relativity theory and the as it could be applied to gravity, quantum mechanics and the theory of light. These ideas still remain fundamental in science today.
I became interested in the work of Albert Einstein because of the fact that is work is fundamental to the understanding of quantum mechanics and the idea of gravity. He laid the foundation upon which modern physics is built.
Learn more about Albert Einstein:brainly.com/question/2964376
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16) you can tell which craters are younger by them being small and you can tell which craters are older by them being larger.
17) The larger craters experienced energetic impacts because they are simply larger in size which makes them being impacted.
Hope this was helpful have a nice day :)
the answer would be iron. divide mass by volume to get density.
Oxidizing agent is that which is reduced and the reducing agent is that which is oxidized. Reduced is when the charged is decreased and oxidized when the charge is increased.
(1) 2Na + 2H2O(l) --> 2NaOH(aq) + H2(g)
The charge of Na in the reactant is 0 and the charge of Na in the NaOH is +1. Na is oxidized. Hence, it is the reducing agent.
The charge of H in H2O is +1 while that in H2 is 0. H is reduced. Hence, it is the oxidizing agent.
(2) C(s) + O2(g) --> CO2(g)
The charge of C in the reactant side is 0 and that its charge in CO2 is +4. C is oxidized. Hence, it is the reducing agent.
The charge of O in O2 is 0 while in CO2, its charge is -2. O is reduced. Hence, it is the oxidizing agent.
(3) 2MnO⁻⁴ + SO2 + 2H2O --> 2Mn²⁺ + 5SO2⁻⁴ 4H⁺
The charge of Mn in MnO⁻⁴ is 4+ while its charge in Mn²⁺ is 2+. Mn is reduced. Hence, it is the oxidizing agent.
The charged of S in SO2 is -4 while its charge in SO₂⁻⁴ is 0. S is oxidized. Hence, it is the reducing agent.
