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umka2103 [35]
3 years ago
8

How much energy is required to vaporize 18.32 grams of water at its boiling point?​

Chemistry
1 answer:
Daniel [21]3 years ago
4 0

That is, water has a high heat of vaporization, the amount of energy needed to change one gram of a liquid substance to a gas at constant temperature. Water's heat of vaporization is around 540 cal/g at 100 °C, water's boiling point.
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Plsss help i need help y’all pls help me asap i don’t wanna get a bad grdeee
evablogger [386]

Answer:

The food coloring mixes through the hot water faster than it mixes with the cold water. This is because in hot water, thewater molecules have more energy and are moving faster than the molecules of cold water. This makes it easier for the dye to get mixed throughout the hot water.

5 0
3 years ago
Which is not a name to describe global winds A) Polar Easterlies B) Prevailing Westerlies C) Trade Winds D) Tropical Northerlies
SVEN [57.7K]
D Tropical northerlies
8 0
4 years ago
Read 2 more answers
Classify the carbohydrate tagatose by both the carbonyl group and the number of carbon atoms. D-tagatose is sugar with six carbo
Bingel [31]

Answer:

Hexose category and ketohexose category

Explanation:

The classification of the Carbohydrate tagatose by carbonyl group is that it is a monosaccharide and has a hexose structure hence it belongs to the Hexose category

Based on the number of carbon atoms the structure has a ketofunctionality hence it is classified under the ketohexose category

Attached below is the remaining part of the solution

6 0
3 years ago
In a Lewis diagram for methane (CH4), which atom or atoms is inside, or central?
Ahat [919]

Answer:

B carbon

Explanation

Lewis structure or dot structure is an easy way to get the bonding details of atoms in a molecule. If we talk about methane molecule carbon is central atom with four electrons that are bonded to four hydrogen atoms and each bond is single covalent bond.

Please see attached figure,

Hope it helps!

7 0
3 years ago
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A helium filled ballon had a volume of 8.50 L on the ground at 20.0 C and a pressure of 750.0 Torr. After the ballon was release
Marrrta [24]

Answer:

V_2=12.1L

Explanation:

Hello!

In this case, according to the given data of volume, pressure and temperature, it is possible to infer this problem can be solved via the combined gas law:

\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}

Thus, regarding the question, we evidence we need V2, but first we make sure the temperatures are in Kelvins:

T_1=20+273=293K\\\\T_2=-40+273=233K

Then, we obtain:

V_2=\frac{P_1V_1T_2}{T_1P_2}\\\\V_2=\frac{0.987atm*8.50L*233K}{293K*0.550atm}\\\\V_2=12.1L

Best regards!

5 0
3 years ago
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