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umka2103 [35]
3 years ago
8

How much energy is required to vaporize 18.32 grams of water at its boiling point?​

Chemistry
1 answer:
Daniel [21]3 years ago
4 0

That is, water has a high heat of vaporization, the amount of energy needed to change one gram of a liquid substance to a gas at constant temperature. Water's heat of vaporization is around 540 cal/g at 100 °C, water's boiling point.
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Name the three sub particle of an atom, their charges and their mass.
muminat

The three sub particles of an atom are protons, electrons and neutrons.

<u>Explanation:</u>

Neutrons, electrons, and protons are the three sub atomic particles of an atom. Electrons are negatively charged, protons are the positively charged and neutrons are neutral. Electrons are having 9.1×10^{-31} kg, protons and neutrons are having a mass of 1.67×10^{-24} kg.

As protons possess positive charges, so the atomic number of protons will be 1 , similarly, the atomic number of electrons will be -1 and neutron is zero. So, electrons, protons and neutrons combine together to form the atom.

As the electrons present with negative charge and protons with positive charge, along with this the protons number are equal to electrons number, this confirm the neutral nature of atoms.

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3 years ago
How many moles are there in 3.9 grams of potassium
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Explanation:

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3 years ago
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bulgar [2K]

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Explanation :

Molarity : Molarity is defined as the moles of solute present in one liter of the solution. Or it is defined as the concentration of solute present in one liter of solution.

The unit of molarity is, (M) i.e, mole/liter. It is also known as molar concentration.

Molarity of 0.01 M means, 0.01 concentration of the acid present in the solution.

Therefore, the 0.01 M refer to the concentration of the acid.

5 0
4 years ago
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A chemist prepares a solution by adding 258 mg of K2Cr2O7 (MW = 294.19 g/mol ) to a volumetric flask, and then adding water unti
Maksim231197 [3]

Answer: Molarity of the prepared solution is 1.75\times 10^{-3}mole/L

Explanation:

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Molarity=\frac{n\times 1000}{V_s}

where,

n= moles of solute

V_s = volume of solution in ml = 500 ml

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Now put all the given values in the formula of molarity, we get

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Thus molarity of the prepared solution is 1.75\times 10^{-3}mole/L

3 0
3 years ago
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