Answer:
The correct option is: CO₂
Explanation:
Greenhouse effect refers to the natural phenomenon by which the Sun's radiation increases the temperature of the Earth's surface.
The incoming Sun's radiation is radiated by the greenhouse gases present in the Earth's atmosphere. A fraction of the radiated energy is then absorbed by the Earth's surface, thus resulting in increase in the temperature.
<u>Thus the green house effect depends upon the amount of green house gases present in the atmosphere.</u>
The green house gases are the r<u>adiatively active gases.</u> The main four green house gases are: water vapor (H₂O(g)), carbon dioxide (CO₂), methane (CH₄) and ozone (O₃).
<u>Human activities such as burning of fossil gases and deforestation increases the concentration of </u><u>CO₂ </u><u>significantly.</u><u> Thereby contributing to the greenhouse effect.</u>
Answer:47.05% is the percent yield of nitrogen in the reaction.
Explanation:
heoretical yield of nitrogen gas = x
Moles of ammonia =
According to reaction,2 moles of ammonia gives 1 mol of nitrogen gas.
Then 2.3529 mol of ammonia will give:
of nitrogen gas
Mass of 1.1764 moles of nitrogen gas,x = 1.1764 mol × 28 g/mol=32.94 g
Experiential yield of nitrogen gas = 15.5 g
Percentage yield:
hope that help
47.05% is the percent yield of nitrogen in the reaction.
A cl2 molecule is a diatomic molecule composed of two atoms of identical halogen - chlorine. In this case, this molecule is composed of covalent bonds in which the identical atom- molecule tells that this is also non-polar. To break the bond, energy has to be absorbed to break the intermolecular force that bound the molecule together.
The answer should be neutrons electrons and protons
By definition, one mole (one gram molecular weight) of any substance, contains Avogadro’s number of particles; atoms if you are discussing an element, or molecules if a compound. Avogadro’s number has been determined by several methods, all of the accepted values lie within a range of +-1% about the value of 6.022045 x 10^23/gm. That is a large number, in this case approximately; 602,204,500,000,000,000,000,000 molecules of glucose.
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