Answer:
b
Explanation:
exothermic... heat is released
199.5 g of sucrose is needed to make 665 ml of 30 % weight by volume percent solution.
<h3>What is percent solution?</h3>
Percent solution is defined as a convenient way to record concentration of solution.It is a expression which relates solute to solvent as,mass of solute/mass of solution ×100.There are two types of percentage solutions percent weight by volume and percent volume by volume .Advantages of using percent solutions is that molecular weight of compound is not required.
This example is percent weight by volume where mass of solute is calculated as,%(w/v)= mass of solute/mass of solution×100
substitution of values gives,30×665/100=199.5 g
Thus ,199.5 g of sucrose is required to make 665 ml of 30 % sucrose solution.
Learn more about percent solutions,here:
brainly.com/question/18061219
#SPJ1
Answer:
Word that comes from a Greek word
Explanation:
Glucose is a natural monosaccharide, which has the following molecular formula: C6H12O6
From the chemical point of view, this molecule is a hexose (this is, it has 6 carbon atoms) and an aldose (since it has an aldehyde group)
Glucose as a word has its origin from the Greek word “gleukos”, which means “sweet wine”, and the suffix “ose”, which is used to for a sugar
French people then adapted this word (in order to define a new chemical word, to differentiate the type of sugar found in grapes, slight different from sugar found in other elements such as honey)
<span>The six noble gases that occur naturally are helium (He), neon (Ne), argon (Ar), krypton (Kr), xenon (Xe), and the radioactive radon (Rn).</span>
Rate of Effusion of Unknown gas = rX = 0.5
Rate of Effusion of Hydrogen = rH = 1
M.mass of Hydrogen = mH = 2 g/mol
M.mass of Unknown gas = mX = ?
Formula used:
rH / rX = √mX / mH
taking square on both sides,
r²H / r²X = mX / mH
Solving for mX,
mX = (r²H ÷ r²X) × mH
Putting values,
mX = [1² ÷ (0.5)²] × 2 g/mol
mX = (1 ÷ 0.25) × 2 g/mol
mX = 4 × 2 g/mol
mX = 8 g/mol
Result:
Molecular Mass of Unknown gas is 8 g/mol.