The values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30
<h3>How to rewrite in vertex form?</h3>
The equation is given as:
f(x) = x^2 + 12x + 6
Rewrite as:
x^2 + 12x + 6 = 0
Subtract 6 from both sides
x^2 + 12x = -6
Take the coefficient of x
k = 12
Divide by 2
k/2 = 6
Square both sides
(k/2)^2 = 36
Add 36 to both sides of x^2 + 12x = -6
x^2 + 12x + 36= -6 + 36
Evaluate the sum
x^2 + 12x + 36= 30
Express as perfect square
(x + 6)^2 = 30
Subtract 30 from both sides
(x + 6)^2 -30 = 0
So, the equation f(x) = x^2 + 12x + 6 becomes
f(x) = (x + 6)^2 -30
A quadratic equation in vertex form is represented as:
f(x) = a(x - h)^2 + k
Where:
Vertex = (h,k)
By comparison, we have:
(h,k) = (-6,-30)
Hence, the values of h and k when f(x) = x^2 + 12x + 6 is in vertex form is -6 and -30
Read more about quadratic functions at:
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For the parallel lines 1/2 the vertical line is 1 & the horizontal line is 2 so if you multiply both of them should equal 3. I don't acually know about the other one though
Answer:
m = -1
Step-by-step explanation:
use the slope formula so m = 1- -2 / -1 - 2
m = 1+2/-3, m=3/-3 so m = -1
A represents his age nowa + 56 = 9a Can you solve for a?
The correct answer to this question is letter "B. equilateral." Complete this statement: A polygon with all sides the same length is said to be equilateral.
Equilateral means all sides are the same length, equiangular means all angles are the same degrees, and regular means both equiangular and equilateral. Convex means that the interior angles can have a maximum of 180 degrees each; no vertexes can point to the center.<span>
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