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3 years ago

Why can steam at 100°C cause more severe burns than the same mass of liquid water at 100°C?

Physics

2 answers:

sergejj [24]3 years ago

5 0

HEY THERE!!

CORRECT ANSWER :- B.The steam has more thermal energy than the liquid water.

Hope it helps you.

harina [27]3 years ago

3 0

The answer is B.The steam has more thermal energy than the liquid water.

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Our solar system formed from a huge cloud of dust and gas called a _____.

Mumz [18]

Our solar system formed from a huge cloud of dust and gas called a
c. solar nebula

Based on the nebular hypothesis, our solar system formed from hydrogen gas and interstellar dust. The gas and the dust contracted and formed the early stage of the sun.

7 0

3 years ago

Read 2 more answers

. A person travels by car from one city to another with different constant speeds between pairs of cities. She drives for 30.0 m

love history [14]

<span>
Total distance covered = 40+20+30 = 90 km

Total time taken to cover this distance = .5 hr + .2 hr + .75 hr = 1.75 hr

Avg. speed of Trip would be
90/1.45 = 62.07 km</span>

7 0

3 years ago

Read 2 more answers

In this week's experiment, you send an unpolarized light beam through two polarizers in series. You orient the first polarizer s

g100num [7]

Answer:

Part a)

$\theta = 90 degree$

so the polarization axis of two polarizers must be at 90 degree

Part b)

$\theta = 20 + 14.3 = 34.3 degree$

(vi) set the second polarizer so that its angular scale reads 34.3 degrees.

Explanation:

Part 1)

As per law of Malus we know that the intensity of light coming from the second polarizer and the intensity of the light from first polarizer is related as

$I = I_o cos^2\theta$

now we know that we rotate the second polarizer till the intensity of the light becomes zero

so we will have

$I = 0$

so we will have

$\theta = 90 degree$

so the polarization axis of two polarizers must be at 90 degree

Part b)

when two axis are inclined at 90 degree then scale reads 104.3 degree

so here the scale exceeds the reading by

$\Delta \theta = 104.3 - 90 = 14.3$

so in order to make them inclined at 20 degree we will have

$\theta = 20 + 14.3 = 34.3 degree$

(vi) set the second polarizer so that its angular scale reads 34.3 degrees.

7 0

4 years ago

In a certain clock, a pendulum of length L1 has a period T1 = 0.95s. The length of the pendulum

gulaghasi [49]

Answer:

Ratio of length will be $\frac{L_2}{L_1}=1.108$

Explanation:

We have given time period of the pendulum when length is $L_1$ is $T_1=0.95sec$

And when length is $L_2$ time period $T_2=1sec$

We know that time period is given by

$T=2\pi \sqrt{\frac{L}{g}}$

So $0.95=2\pi \sqrt{\frac{L_1}{g}}$ ----eqn 1

And $1=2\pi \sqrt{\frac{L_2}{g}}$ -------eqn 2

Dividing eqn 2 by eqn 1

$\frac{1}{0.95}=\sqrt{\frac{L_2}{L_1}}$

Squaring both side

$\frac{L_2}{L_1}=1.108$

8 0

4 years ago

What is benford's law.

Nastasia [14]

Answer:

Known variously as the Newcomb–Benford law, the law of anomalous numbers, or the first-digit law, Benford's Law is the observation that the first digit in many real-world collections of numerical data will be tiny, as shown by the example of the first-digit law.

Explanation:

Hope it helps:)

5 0

2 years ago