A squirrel on a table clothesline is running 3.4 m./s. How far does the squirrel go in 2.5 minutes

When a person's temperature reaches 104 degrees, the chances of survival are decreased dramatically. Group of answer choices Tru

Natali5045456 [20]

Answer:

True

Explanation:

With the increase in temperature hypothalamus fails and heatstroke occurs due to this failure. Hypothalamus is the region of our brain that act as a thermostat. It co-ordinates our physiological response to excessive heat. When the person’s temperature reaches to 104 degrees then it causes heatstroke. This heatstroke is very sudden and can kill person. Hence, we can conclude that when person’s temperature reaches to 104 degrees chances of survival decreases dramatically.

8 0

4 years ago

a body of mass 20kg initially at rest is subjected to a force of 40N for 1sec calculate the change in kinetic energy showing the

Tema [17]

Answer:

Change in KE is 40 J

Explanation:

Recall that the impulse exerted on an object equal the change of momentum of the object (ΔP), which in time is defined as the product of the force exerted on it times the time the force was acting:

Change in momentum is: ΔP = F * Δt

In our case,

ΔP = 40 N * 1 sec = 40 N s

Since the object was initially at rest, its initial momentum was zero, and the final momentum should then be 40 N s.

So, the initial KE was 0, and the final (KEf) can be calculated using:

KEf = 1 /(2 m) Pf^2 = 1 / (40) 40^2 = 40 J

So, the change in kinetic energy is:

KEf - KEi = 40 J - 0 j = 40 J

8 0

3 years ago

A 77.0−kg short-track ice skater is racing at a speed of 12.6 m/s when he falls down and slides across the ice into a padded wal

sukhopar [10]

Answer:

-6112.26 J

Explanation:

The initial kinetic energy, $KE_i$ is given by

$KE_i=0.5mv_1^{2$ } where m is the mass of a body and $v_i$ is the initial velocity

The final kinetic energy, $KE_f$ is given by

$KE_f=0.5mv_f^{2}$ where $v_f$ is the final velocity

Change in kinetic energy, $\triangle KE$ is given by

$\triangle KE=KE_f-KE_i=0.5mv_f^{2}-0.5mv_1^{2}=0.5m(v_f^{2}-v_i^{2})$

Since the skater finally comes to rest, the final velocity is zero. Substituting 0 for $v_f$ and 12.6 m/s for $v_i$ and 77 Kg for m we obtain

$\triangle KE=0.5*77*0^{2}-0.5*77*(0^{2}-12.6^{2})=-6112.26 J$

From work energy theorem, work done by a force is equal to the change in kinetic energy hence for this case work done equals <u>-6112.26 J</u>

3 0

3 years ago

Two identical balls each have a mass of 35.0 grams and a charge of . The balls are released from rest when they are separated by

OlgaM077 [116]

The given question is incomplete. The complete question is as follows.

Two identical balls each have a mass of 35.0 grams and a charge of q = 3.50 \times 10^{-6}C[/tex]. The balls are released from rest when they are separated by a distance of 6.00 cm. What is the speed of each ball when the distance between them has tripled? Use k = $9.00 \times 10^{9} Nm^{2}/C^{2}$ .

Explanation:

According to the conservation of energy, the formula will be as follows.

$\frac{kq_{1}q_{2}}{r_{1}} = \frac{kq_{1}q_{2}}{(3r_{1})} + \frac{1}{2}mv^{2} + \frac{1}{2}mv^{2}$

or, $\frac{kq_{1}q_{2}}{r_{1}}[1 - \frac{1}{3}] = mv^{2}$

Putting the given values into the above formula as follows.

$\frac{kq_{1}q_{2}}{r_{1}}[1 - \frac{1}{3}] = mv^{2}$

$\frac{9 \times 10^{9} \times (3.5 \times 10^{-6})^{2}}{0.09} \times \frac{2}{3} = \frac{35}{1000}v^{2}$

$v^{2}$ = 23.333

v = 4.83 m/s

Thus, we can conclude that speed of each ball when the distance between them has tripled is 4.83 m/s.

7 0

4 years ago

The portion of a light ray that falls on a surface is a/an

rosijanka [135]

<span>The correct answer is an incident ray. The ray that is reflected is always reflected at the same angle at which the incident ray hits the surface. This of course only applies if it hits a straight surface, since hitting a lense would be different as it might reflect under a different angle or it might not even reflect.</span>

3 0

3 years ago