1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
babymother [125]
3 years ago
6

Each plate of an air-filled parallel-plate capacitor has an area of 45.0 cm2, and the separation of the plates is 0.080 mm. A ba

ttery with voltage V is attached to the capacitor and an energy density of u- 100 J/m is stored between the plates. Determine the amount of charge that this capacitor has on its positive plate. (Watch the prefixes-they are not all the same) a. 8.8 pC b. 0.75 nC c. 28 nC d. 84 nC e. 190 nC
Physics
1 answer:
maw [93]3 years ago
3 0

Answer:

Option (e)

Explanation:

A = 45 cm^2 = 0.0045 m^2, d = 0.080 mm = 0.080 x 10^-3 m,

Energy density = 100 J/m

Let Q be the charge on the plates.

Energy density = 1/2 x ε0 x E^2

100 = 0.5 x 8.854 x 10^-12 x E^2

E = 4.75 x 10^6 V/m

V = E x d

V = 4.75 x 10^6 x 0.080 x 10^-3 = 380.22 V

C = ε0 A / d

C = 8.854 x 10^-12 x 45 x 10^-4 / (0.080 x 10^-3) = 4.98 x 10^-10 F

Q = C x V = 4.98 x 10^-10 x 380.22 = 1.9 x 10^-7 C

Q =  190 nC

You might be interested in
Honeybees accumulate charge as they fly, and they transfer charge to the flowers they visit. Honeybees are able to sense electri
Vilka [71]

Answer:

ΔE> E_minimo

We see that the field difference between these two flowers is greater than the minimum field, so the bee knows if it has been recently visited, so the answer is if it can detect the difference

Explanation:

For this exercise let's use the electric field expression

         E = k q / r²

where k is the Coulomb constant that is equal to 9 109 N m² /C², q the charge and r the distance to the point of interest positive test charge, in this case the distance to the bee

let's calculate the field for each charge

 

Q = 24 pC = 24 10⁻¹² C

         E₁ = 9 10⁹ 24 10⁻¹² / 0.20²

         E₁ = 5.4 N / C

Q = 32 pC = 32 10⁻¹² C

         E₂ = 9 10⁹ 32 10⁻¹² / 0.2²

         E₂ = 7.2 N / C

let's find the difference between these two fields

         ΔE = E₂ -E₁

         ΔE = 7.2 - 5.4

         ΔE = 1.8 N / C

the minimum detection field is

         E_minimum = 0.77 N / C

        ΔE> E_minimo

We see that the field difference between these two flowers is greater than the minimum field, so the bee knows if it has been recently visited, so the answer is if it can detect the difference

8 0
2 years ago
A rocket fires its engines to launch straight up from rest
alexira [117]
Weow that’s cool but what is your question
3 0
3 years ago
A racquet ball with mass m = 0.221 kg is moving toward the wall at v = 13.9 m/s and at an angle of θ = 25° with respect to the h
Salsk061 [2.6K]

Answer:

1) 3.07kgm/s

2) 5.56kgm/s

3) 76.16N

4) 4.33kgm/s

5) 0.57s

6) -8.66J

Explanation:

Given

m = 0.221kg

v = 13.9m/s

θ = 25°

t = 0.073s

1) to get the magnitude of the initial momentum is the racquet ball. We use the formula,

P(i) = mv(i)

P(i) = 0.221 * 13.9

P(i) = 3.07kgm/s

2) Magnitude of the change in momentum of the ball,

P(i,x) = P(i) cos θ

P(i,x) = 3.07 * cos25

P(i,x) = 3.07 * 0.9063

P(i,x) = 2.78

ΔP = 2P(i,x)

ΔP = 2 * 2.78 = 5.56kgm/s

3) magnitude of the average force exerted by the wall,

F(ave) = ΔP/Δt

F(ave) = 5.56/0.073

F(ave) = 76.16N

4) ΔP(z) = mv(f) - mv(i)

ΔP(z) = 0.221*-7.8 - 0.221*11.8

ΔP(z) = -1.72 - 2.61

ΔP(z) = 4.33kgm/s

5) F(ave) = ΔP/Δt

Δt = ΔP/F(ave)

Δt = 4.33 / 76.16

Δt = 0.57s

6) KE(i) = 0.5mv(i)²

KE(f) = 0.5mv(f)²

ΔKE = 0.5m[v(f)² - v(i)²]

ΔKE = 0.5 * 0.221 [(-7.8)² - 11.8²]

ΔKE = 0.1105 ( 60.84 - 139.24 )

ΔKE = 0.1105 * -78.4

ΔKE = -8.66J

6 0
3 years ago
How much work is needed to lift a barbell that has a weight of 445 N a total of 2 meters off ground
AleksAgata [21]

Answer:

Total work done to lift barbell = 890 J

Explanation:

Given:

Weight of barbell (F) = 445 N

Height (Distance) = 2 meter

Find:

Total work done to lift barbell = ?

Computation:

⇒ Work = Force(F) × Distance

⇒ Total work done to lift barbell = Weight of barbell × Distance

⇒ Total work done to lift barbell = 445 N × 2 meter

⇒ Total work done to lift barbell = 890 J

5 0
3 years ago
Levi and Clara are trying to move a very heavy box. Levi is pushing the box with a force of 30 N, and Clara is pulling the box w
musickatia [10]
The net force on the box is:
50 + 30 - 65
= 15 Newtons
This can be used in conjunction with
F = ma
to calculate the acceleration of the box if its mass is known.
3 0
3 years ago
Other questions:
  • A microwave works by focusing microwave light on the food inside of it. Which type of energy transformation takes place in a mic
    13·2 answers
  • If an object moves twice as fast how do you think its energy changes? halves
    7·1 answer
  • True or false: When an object becomes polarized, it acquires a charge and becomes a charged object.​
    7·1 answer
  • Would You Rather...Carry a 50 lb box up 3 flights of stairs or a 25 lb box up 5 flights of stairs? Whichever choice you make, ju
    7·1 answer
  • An electron is moving directly toward you in a horizontal path when it suddenly enters a uniform magnetic field that is either v
    15·1 answer
  • A compact car moving at 60 m/s has 320,000 J of kinetic energy. What is its mass?
    8·1 answer
  • A coconut is attached to a palm
    10·1 answer
  • Which of the following provides alternating current? Select all that apply.
    11·1 answer
  • Can mechanical energy be used to do work?
    8·1 answer
  • You have two windlasses (winches) named X and Y. Windlass X drum diameter is 50cm and windlass Y drum diameter is 75cm. Both are
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!