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irinina [24]
2 years ago
10

Which of the following correctly described a compound

Chemistry
1 answer:
victus00 [196]2 years ago
5 0

Answer:

We need the options to answer.

Explanation:

N/A

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Urea, CO(NH2)2, is manufactured on a large scale for use in producing urea-formaldehyde plastics and as a fertilizer. What is th
Pachacha [2.7K]

Answer:

5.004kg

Explanation:

Combustion of carbon

C+O2=CO2

from the relationship of molar ratio

mass of carbon/molar mass of carbon=volume of CO2 produced\molar vol(22.4 dm3)

mass of carbon =1000kg

atomic mass of carbon =12

volume of CO2 produced=1000×22.4/12

volume of CO2 produced =1866.6dm3

from the combustion reaction equation provided

CO2 (g) + 2NH3 (g) ⟶ CO (NH2 )2 (s) + H2 O(l)

applying the same relationship of molar ratio

no of mole of CO2=no of mole of urea

therefore

vol of CO2\22.4=mass of urea/molar mass of urea

molar mass of urea=60.06g/mol

from the first calculation

vol of CO2=1866.6dm3

mass of urea=1866.6×60.06/22.4

mass of urea=5004.82kg

7 0
3 years ago
Read 2 more answers
In preparation for a blizzard, a city dispatches a crew to spread salt on the street surface of the bridges around town. The sal
Ilia_Sergeevich [38]
0 degrees to -6 or -16 degrees Celsius

3 0
3 years ago
C9H20 +<br> 02 - &gt; CO2 +<br> H2O<br><br> what is the balanced equation of this
san4es73 [151]

Hey there!

C₉H₂O + O₂ → CO₂ + H₂O

First let's balance the C.

There's 9 on the left and 1 on the right. So, let's add a coefficient of 9 in front of CO₂.

C₉H₂O + O₂ → 9CO₂ + H₂O

Next let's balance the H.

There's 2 on the left and 2 on the right. This means it's already balanced.

C₉H₂O + O₂ → 9CO₂ + H₂O

Lastly, let's balance the O.

There's 3 on the left and 19 on the right. So, let's add a coefficient of 9 in front of O₂.

C₉H₂O + 9O₂ → 9CO₂ + H₂O

This is our final balanced equation.

Hope this helps!

8 0
2 years ago
What is the final concentration of a solution prepared by diluting 35.0 ml of 12.0 m hcl to a final volume of 1.20 l? what is th
Dafna1 [17]
We know that, M1V1     =     M2V2
                        (Initial)          (Final)
where, M1 and M2 are initial and final concentration of soution respectively. 
V1 and V2 = initial and final volume of solution respectively

Given: M1 = 12 m, V1 = 35 ml and V2 = 1.2 l = 1200 ml

∴ M2 = M1V1/V2 = (12 × 35)/ 1200 = 0.35 m
Final concentration of solution is 0.35 m
8 0
3 years ago
complete the name of an alkali that could react with phosphoric acid to make sodium hydrogen phosphate
elena-s [515]
The answer is sodium hydroxide
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2 years ago
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