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irinina [24]
3 years ago
10

Which of the following correctly described a compound

Chemistry
1 answer:
victus00 [196]3 years ago
5 0

Answer:

We need the options to answer.

Explanation:

N/A

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Mass = 100g, volume=20ml, what is density?
Nonamiya [84]

Answer:

<h3>The answer is 5.0 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 100 g

volume = 20 mL

So we have

density =  \frac{100}{20}  \\

We have the final answer as

<h3>5.0 g/mL</h3>

Hope this helps you

4 0
3 years ago
What is formed when sediment is blown against an obstacle and settles behind it
Naddik [55]
The answer should be "Dunes"
4 0
3 years ago
How many moles of oxygen gas molecules would you need to make 12.5 moles of water
horrorfan [7]

Answer: 6.25 mol

Explanation:

From the reaction that produces water from its elements (shown in the image), we know that for every mole of oxygen gas consumed, 2 moles of water are produced.

This means that 12.5/2=<u>6.25 mol</u> of oxygen gas is needed.

7 0
2 years ago
Does it take more, less, or the same amount of heat to melt 1.0 kg of ice at 0°C, or to bring 1.0 kg of liquid water at 0°C to t
Murljashka [212]

Answer : It takes less amount of heat to metal 1.0 Kg of ice.

Solution :

The process involved in this problem are :

(1):H_2O(s)(0^oC)\rightarrow H_2O(l)(0^oC)\\\\(2):H_2O(l)(0^oC)\rightarrow H_2O(l)(100^oC)

Now we have to calculate the amount of heat released or absorbed in both processes.

<u>For process 1 :</u>

Q_1=m\times \Delta H_{fusion}

where,

Q_1 = amount of heat absorbed = ?

m = mass of water or ice = 1.0 Kg

\Delta H_{fusion} = enthalpy change for fusion = 3.35\times 10^5J/Kg

Now put all the given values in Q_1, we get:

Q_1=1.0Kg\times 3.35\times 10^5J/Kg=3.35\times 10^5J

<u>For process 2 :</u>

Q_2=m\times c_{p,l}\times (T_{final}-T_{initial})

where,

Q_2 = amount of heat absorbed = ?

m = mass of water = 1.0 Kg

c_{p,l} = specific heat of liquid water = 4186J/Kg^oC

T_1 = initial temperature = 0^oC

T_2 = final temperature = 100^oC

Now put all the given values in Q_2, we get:

Q_2=1.0Kg\times 4186J/Kg^oC\times (100-0)^oC

Q_2=4.186\times 10^5J

From this we conclude that, Q_1 that means it takes less amount of heat to metal 1.0 Kg of ice.

Hence, the it takes less amount of heat to metal 1.0 Kg of ice.

5 0
3 years ago
Explain the ingredients of ice-cream, the state and why the state in which it is sold is important​
Eva8 [605]

Answer:

Go on the site named " the chemistry of ice cream ''

Explanation:

https://davidson.weizmann.ac.il/en/online/sciencepanorama/chemistry-ice-cream

4 0
2 years ago
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