Answer:
Tc^(+7) - 2.35*10^-5M
PO4(^-3) - 5.50*10^-5M
Explanation:
Tc3(PO4)7 <---> 
1 mol 3 mol 7 mol
7.85 X 10^-6 M 3*7.85*10^-6M 7*7.85*10^-6M
2.35*10^-5M 5.50*10^-5M
Answer:
D. All of them would have the same kinetic energy
Explanation:
The expression for the kinetic energy of the gas is:-
k is Boltzmann's constant = 
T is the temperature
<u>Since, kinetic energy depends only on the temperature. Thus, at same temperature, at 300 K, all the gases which are 
will posses same value of kinetic energy.</u>
The dissociation of both salts NaCl and CaCl₂ are as follows;
NaCl --> Na⁺ + Cl⁻
CaCl₂ --> Ca²⁺ + 2Cl⁻
the molar ratio of NaCl to Cl⁻ is 1:1
therefore number of NaCl moles is equal to number of Cl⁻ ions dissociated from NaCl
then number of Cl⁻ ion moles - 0.233 mol/L x 0.1000 L = 0.0233 mol
molar ratio of CaCl₂ to Cl⁻ ions is 1:2
1 mol of CaCl₂ gives out 2 mol of Cl⁻ ions.
number of CaCl₂ moles - 0.150 mol/L x 0.2500 L = 0.0375 mol
then the number of Cl⁻ ion moles - 0.0375 x 2 = 0.0750
total number of Cl⁻ ion moles = 0.0233 mol + 0.0750 mol = 0.0983 mol
volume of solution - 100.0 + 250.0 = 350.0 mL
concentration of Cl⁻ = 0.0983 mol / 0.3500 L = 0.281 M
concentration of Cl⁻⁻ is 0.281 M
