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kipiarov [429]
3 years ago
5

What is importance of thermometer?​

Chemistry
1 answer:
Misha Larkins [42]3 years ago
4 0
A laboratory thermometer is used to measure the boiling point and freezing point during science experiments. it is also used to measure the temperature of substances. It measures temperature ranging between -10 degree Celsius and 110 degree Celsius :)
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What is the concentration of each ion in 15.00 ml of a 7.85 X 10^-6 M solution of Tc3 (PO4)7?
Daniel [21]

Answer:

Tc^(+7)    -    2.35*10^-5M  

PO4(^-3)  -   5.50*10^-5M

Explanation:

Tc3(PO4)7  <--->              3Tc^{7+} + 7PO_{4}^{3-}

1 mol                                3 mol      7 mol

7.85 X 10^-6 M    3*7.85*10^-6M       7*7.85*10^-6M

                            2.35*10^-5M          5.50*10^-5M

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3 years ago
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8 0
3 years ago
Read 2 more answers
Which of the following gases would have the greatest kinetic energy at 300 K?
tekilochka [14]

Answer:

D. All of them would have the same kinetic energy

Explanation:

The expression for the kinetic energy of the gas is:-

K.E.=\frac{3}{2}\times K\times T

k is Boltzmann's constant = 1.38\times 10^{-23}\ J/K

T is the temperature

<u>Since, kinetic energy depends only on the temperature. Thus, at same temperature, at 300 K, all the gases which are N_2,\ NH_3\ and\ Ar will posses same value of kinetic energy.</u>

4 0
3 years ago
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kari74 [83]

Answer:

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Explanation:

6 0
3 years ago
Calculate the concentration of chloride ions when 100.0 mL of 0.233 M sodium chloride is mixed with 250.0 mL of 0.150 M calcium
serg [7]
The dissociation of both salts NaCl and CaCl₂ are as follows;
NaCl --> Na⁺ + Cl⁻

CaCl₂ --> Ca²⁺ + 2Cl⁻

the molar ratio of NaCl to Cl⁻ is 1:1
therefore number of NaCl moles is equal to number of Cl⁻ ions dissociated from NaCl
then number of Cl⁻ ion moles - 0.233 mol/L x 0.1000 L = 0.0233 mol

molar ratio of CaCl₂ to Cl⁻ ions is 1:2
1 mol of CaCl₂ gives out 2 mol of Cl⁻ ions.
number of CaCl₂ moles - 0.150 mol/L x 0.2500 L  = 0.0375 mol 
then the number of Cl⁻ ion moles - 0.0375 x 2 = 0.0750 

total number of Cl⁻ ion moles = 0.0233 mol + 0.0750 mol = 0.0983 mol
volume of solution - 100.0 + 250.0 = 350.0 mL 

concentration of Cl⁻ = 0.0983 mol / 0.3500 L = 0.281 M
concentration of Cl⁻⁻ is 0.281 M 
4 0
3 years ago
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