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harina [27]
3 years ago
15

What is the concentration of each ion in 15.00 ml of a 7.85 X 10^-6 M solution of Tc3 (PO4)7?

Chemistry
1 answer:
Daniel [21]3 years ago
5 0

Answer:

Tc^(+7)    -    2.35*10^-5M  

PO4(^-3)  -   5.50*10^-5M

Explanation:

Tc3(PO4)7  <--->              3Tc^{7+} + 7PO_{4}^{3-}

1 mol                                3 mol      7 mol

7.85 X 10^-6 M    3*7.85*10^-6M       7*7.85*10^-6M

                            2.35*10^-5M          5.50*10^-5M

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Calculate the molar solubility of silver(i) bromate with ksp = 5. 5×10-5. also, convert the molar solubility to the solubility.
Sindrei [870]

The molar solubility is 7.4×10^{-3} M and the solubility is  7.4×10^{-3} g/L .

Calculation ,

The dissociation of silver bromide is given as ,

AgBr → Ag ^{+} + Br^{-}

S  

 -          S        S        

Ksp =  [Ag ^{+} ] [ Br^{-} ]  =  [S] [ S ] = S^{2}

S = √ Ksp = √ 5. 5×10^{-5} = 7.4×10^{-3}

The solubility =7.4×10^{-3} g/L

The molar solubility is the solubility of one mole of the substance.

Since ,  one mole of AgBr is dissociates and form one mole of each  Ag ^{+} and Br^{-} ion . So, solubility is equal to molar solubility but unit is different.

Molar solubility = 7.4×10^{-3} mol/L = 7.4×10^{-3} M

To learn more about molar solubility ,

brainly.com/question/16243859

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7 0
1 year ago
How does water’s high specific heat capacity affect large lakes?
soldi70 [24.7K]
<h2>Answer:</h2>

The water has higher specific heat capacity which affects the lakes largely in such way that the water in a lake changes temperature slowly.

<h2>Explanation:</h2>

Evaporation is a process of liquid changing its state to gaseous state at any temperature. Water has high specific heat due to the presence of strong hydrogen bonds. Due to which it requires heat in huge amount to raise the water (in large quantity) temperature.

Thus, the molecules will be unable to gain much kinetic energy that result in changing the temperature very slowly.

7 0
3 years ago
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Answer:

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Explanation:

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We subtract the two

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Scientists use carbon-14 to date ancient fossils.

Plants and animals absorb carbon-14 produced by cosmic rays. The ratio of C-14 to C-12 is constant when they are alive.

When they die, the C-14 decays to C-12, and the ratio changes.

Carbon-14 has a half-life of 5730 years. Thus, the object loses half its C-14 every 5730 years.

Scientists can use the C-14 to C-12 ratio to date fossils up to 70 000 years old.

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Whent he people went to the moon they told them what it was

Explanation:

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