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love history [14]
2 years ago
7

How can we prepare for climate change?? Plzzzzzzzz helppppppo

Chemistry
2 answers:
tino4ka555 [31]2 years ago
8 0
stop farting. hehehehehhehe
Novosadov [1.4K]2 years ago
3 0

Answer:

WE start by having all the thing s that would be necessary at that time so we would have to worry about what we don't or won't have if you do before hand.  

Explanation:

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Write the symbol of another isotope of lead with 132 neutrons.
Ivahew [28]

Answer:

Pb^+7

Explanation:

I placed the carrot there to signify the +7 is supposed to be small. It is plus seven because seven nuetrons are added

5 0
3 years ago
Carbon dioxide gas is produced by the reaction of oxygen gas and solid carbon . Write a balanced chemical equation for this reac
grandymaker [24]

I think it’s like this.

C+2O→CO2

5 0
3 years ago
What is the notation for the enthalpy of solution?
Tomtit [17]
The enthalpy<span> of </span>solution<span>, </span>enthalpy<span> of dissolution, or heat of </span>solution<span> is the</span>enthalpy<span> change associated with the dissolution of a substance in a solvent at constant pressure resulting in infinite dilution. The </span>enthalpy<span> of </span>solution<span> is most often expressed in kJ/mol at constant temperature. </span>
4 0
2 years ago
Read 2 more answers
How does energy transfer from the sun to earth and the atmosphere
kumpel [21]

through conduction, radiation, and convection.

4 0
2 years ago
A buffer solution contains 0.479 M NaHCO3 and 0.342 M Na2CO3. Determine the pH change when 0.091 mol HNO3 is added to 1.00 L of
pshichka [43]

Answer:

ΔpH = 0.20

Explanation:

The buffer of HCO₃⁻ + CO₃²⁻ has a pka of 10.2

HCO₃⁻ ⇄ H⁺ + CO₃²⁻

There are 0.479moles of NaHCO₃ and 0.342moles of Na₂CO₃.

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.342mol / 0.479mol

<em>pH = 10.05</em>

NaOH reacts with HCO₃⁻ producing CO₃²⁻, thus:

NaOH + HCO₃⁻ → CO₃²⁻ + H₂O + Na⁺

0.091 moles of NaOH produce the same moles of CO₃²⁻ and consume HCO₃⁻. Moles of these species are:

CO₃²⁻: 0.342mol + 0.091mol: 0.433mol

HCO₃⁻: 0.479mol - 0.091 mol: 0.388mol

Using Henderson-Hasselbalch formula:

pH = pka + log [Base] / [Acid]

pH = 10.2 + log 0.433mol / 0.388mol

pH = 10.25

That means change of pH, ΔpH is:

ΔpH = 10.25 - 10.05 = <em>0.20</em>

<em />

I hope it helps!

3 0
2 years ago
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