Answer:
is high as 100 degrees c
Explanation:
due to high heat gas expands fast than normal
Answer:
The magnitude of the free-fall acceleration at the orbit of the Moon is (, where ).
Explanation:
According to the Newton's Law of Gravitation, free fall acceleration (), in meters per square second, is directly proportional to the mass of the Earth (), in kilograms, and inversely proportional to the distance from the center of the Earth (), in meters:
(1)
Where:
- Gravitational constant, in cubic meters per kilogram-square second.
- Mass of the Earth, in kilograms.
- Distance from the center of the Earth, in meters.
If we know that , and , then the free-fall acceleration at the orbit of the Moon is:
The potential energy of the skateboarder at the top of the ramp is
489.1 J.
<h3>Is kinetic energy always equal to potential energy?</h3>
The amount of kinetic energy change and the amount of potential energy change are equal in all physical processes that take place in closed systems. When the kinetic energy rises, the potential energy falls, and vice versa.
Potential energy is the stored energy in any object or system as a result of its position or component arrangement. However, external factors like air or height have no effect on it. The energy of a moving object or system is referred to as kinetic energy.
Potential energy = kinetic energy
Potential energy = 1/2mv²
Potential energy = 1/2 × 67×7.3
Potential energy = 489.1 J.
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The derived unit for voltage is named volt.
Answer: 500 Watts
Explanation:
Power is the speed with which work is done. Its unit is Watts (), being .
Power is mathematically expressed as:
(1)
Where is the time during which work is performed.
On the other hand, the Work done by a Force refers to the release of potential energy from a body that is moved by the application of that force to overcome a resistance along a path. It is a scalar magnitude, and its unit in the International System of Units is the Joule (like energy). Therefore, 1 Joule is the work done by a force of 1 Newton when moving an object, in the direction of the force, along 1 meter ( ).
When the applied force is constant and the direction of the force and the direction of the movement are parallel, the equation to calculate it is:
(2)
In this case, we have the following data:
So, let's calculate the work done by Peter and then find how much power is involved:
From (2):
(3)
(4)
Substituting (4) in (1):
(5)
Finally: