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oee [108]
3 years ago
6

Gina's teacher says that Jupiter has a much greater gravitational force than Earth, while the Moon has a much smaller force. How

would Gina's weight and mass change on these surfaces?
Physics
1 answer:
belka [17]3 years ago
8 0
On jupiter there more of a gravitational pull, pulling you closer to the "center" making you weight more.
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A goose waddles 18.0 m north and then 5.00 m east. He then walks 2.00 m south and 2.00 m west. What is the magnitude and directi
olya-2409 [2.1K]
Your answer should be 16.3 m 79.4º east of north
7 0
3 years ago
Urgent! Which is not an example of work? Question 2 options: pushing a box across the floor picking up a box off the floor raisi
OLga [1]

Answer:

trying to push a rock that never moves

Explanation:

8 0
3 years ago
What ocean depth would the volume of an aluminium sphere be reduced by 0.10%
yKpoI14uk [10]

Answer:

6400 m

Explanation:

You need to use the bulk modulus, K:

K = ρ dP/dρ

where ρ is density and P is pressure

Since ρ is changing by very little, we can say:

K ≈ ρ ΔP/Δρ

Therefore, solving for ΔP:

ΔP = K Δρ / ρ

We can calculate K from Young's modulus (E) and Poisson's ratio (ν):

K = E / (3 (1 - 2ν))

Substituting:

ΔP = E / (3 (1 - 2ν)) (Δρ / ρ)

Before compression:

ρ = m / V

After compression:

ρ+Δρ = m / (V - 0.001 V)

ρ+Δρ = m / (0.999 V)

ρ+Δρ = ρ / 0.999

1 + (Δρ/ρ) = 1 / 0.999

Δρ/ρ = (1 / 0.999) - 1

Δρ/ρ = 0.001 / 0.999

Given:

E = 69 GPa = 69×10⁹ Pa

ν = 0.32

ΔP = 69×10⁹ Pa / (3 (1 - 2×0.32)) (0.001/0.999)

ΔP = 64.0×10⁶ Pa

If we assume seawater density is constant at 1027 kg/m³, then:

ρgh = P

(1027 kg/m³) (9.81 m/s²) h = 64.0×10⁶ Pa

h = 6350 m

Rounded to two sig-figs, the ocean depth at which the sphere's volume is reduced by 0.10% is approximately 6400 m.

6 0
3 years ago
Please Answer These Questions I Really Need Help Please answer these questions
wel
1. <span>Onion cells have thick rectangular walls.
2. </span><span>Both are tropospheres, the lobster and fungi have the same outer shell.
3. </span><span>A bat is a mammal--it has fur, lactates and is warm-blooded. Mammals are vertebrates. Vertebrates have a dorsal nerve cord protected by bony or cartilaginous vertebrae. Arthropods are invertebrates--they do not have vertebrae. They are a specific kind of invertebrate with a jointed exoskeleton.
4, 5, 6, 7 - Sorry don't know these answers to these questions

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8 0
3 years ago
The distance that a spring will stretch varies directly as the force applied to the spring. A force of 8080 pounds is needed to
xxTIMURxx [149]

Answer:

F₂= 210 pounds

Explanation:

Conceptual analysis

Hooke's law

Hooke's law establishes that the elongation (x) of a spring is directly proportional to the magnitude of force (F) applied to it, provided that said spring is not permanently deformed:

F= K*x   Formula (1)

Where;

F  is the magnitude of the force applied to the spring in Newtons (Pounds)

K is the elastic spring constant, which relates force and elongation. The higher its value, the more work it will cost to stretch the spring. (Pounds/inch)

x the elongation of the spring (inch)

Data

The data given is incorrect because if we apply them the answer would be illogical.

The correct data are as follows:

F₁ =80 pounds

x₁= 8 inches

x₂= 21  inches

Problem development

We replace data in formula 1 to calculate  K :

F₁= K*x₁

K=( F₁) / (x₁)

K=( 80) / (8) = 10 pounds/ inche

We apply The formula 1 to calculate  F₂

F₂= K*x₂

F₂= (10)*(21)

F₂= 210 pounds

8 0
3 years ago
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