Answer:
Q = 5 L/s
Explanation:
To find the flow you use the following formula (para calcular el caudal usted utiliza la siguiente formula):
V: Volume (volumen) = 200L
t: time (tiempo) = 40 s
you replace the values of the parameters to calculate Q (usted reemplaza los valores de los parámteros V y t para calcular el caudal):
Hence, the flow is 5 L/s (por lo tanto, el caudal es de 5L/s)
The circuit is no longer closed.
Answer:
A₁/A₂ = 0.44
Explanation:
The emissive power of the bulb is given by the formula:
P = σεAT⁴
where,
P = Emissive Power
σ = Stefan-Boltzman constant
ε = Emissivity
A = Surface Area
T = Absolute Temperature of Surface
<u>FOR BULB 1:</u>
Since, emissivity and emissive power are constant.
Therefore,
P = σεA₁T₁⁴ ----------- equation 1
where,
A₁ = Surface Area of Bulb 1
T₁ = Temperature of Bulb 1 = 3000 k
<u>FOR BULB 2:</u>
Since, emissivity and emissive power are constant.
Therefore,
P = σεA₂T₂⁴ ----------- equation 2
where,
A₂ = Surface Area of Bulb 2
T₂ = Temperature of Bulb 1 = 2000 k
Dividing equation 1 by equation 2, we get:
P/P = σεA₁T₁⁴/σεA₂T₂⁴
1 = A₁(3000)²/A₂(2000)²
A₁/A₂ = (2000)²/(3000)²
<u>A₁/A₂ = 0.44</u>
The mass of a particle is 2.2x10⁻¹⁵ kg
Consider smoke particles as an ideal gas
The translational RMS speed of the smoke particles is 2.45x10⁻³ m/s.
<em>v= √3kT/m</em>
<em>where k= 1.38x10⁻²³J/K, T is 288K, and m is the mass of the smoke particle</em>
<em>2.45x10⁻³ = √3x1.38x10⁻²³x288/m</em>
<em>m= 2.2x10⁻¹⁵ kg</em>
Therefore, the mass of a particle is 2.2x10⁻¹⁵ kg.
To learn more about the translational root mean square speed of gases, visit brainly.com/question/6853705
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