In an effort to determine where the company can cut spending, Larry creates
1 answer:
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Answer:
<em>The programming language is not stated; however, I'll answer using Python programming language (</em><em>Se</em><em>e attachment</em><em> </em><em>for</em><em> </em><em>proper </em><em>for</em><em>mat</em><em>)</em>
tuition = 10000
rate = 0.04
for i in range(1,15):
tuition = tuition + tuition * rate
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
Explanation:
<em>The first 2 lines initializes tuition and rate to 10000 and 0.04 respectively</em>
tuition = 10000
rate = 0.04
<em>The next line iterates from year 1 to year 14</em>
for i in range(1,15):
<em>This line calculates the tuition for each year</em>
tuition = tuition + tuition * rate
<em>The next 3 lines prints the tuition for year 1 to year 10</em>
if i <= 10:
print("Year "+str(i)+" tuition:",end=" ")
print(round(tuition,2))
<em>The next 3 lines prints the tuition at the 4th year after year 10 (i.e. year 14)</em>
if i == 14:
print("Tuition 4th year after:",end=" ")
print(round(tuition,2))
