If g(x) =f(x+k) , what is the value of k.

1)How many ways can the letters in the word BOOKKEEPER be arranged? (Must show set-up )

sergeinik [125]

Question 1

There are 5 letters (B, O, K, E, R) and there is a total of 10 letters to make up the word.
There are $\frac{10!}{(10-6)!6!}$ ways of arranging the letters, which equal to 210 ways

Question 2

There are seven swimmers in total.
There are $\frac{7!}{(7-1)!1!}$ ways of choosing the first winner, which is 7 ways
There are $\frac{6!}{(6-1)!1!}$ ways of choosing the second winner, which is 6 ways
There are $\frac{5!}{(5-1)!1!}$ ways of choosing the third winner, which is 5 ways
There are 7×6×5=210 ways of choosing first, second, and third winner

Question 3

The probability of eating an orange and a red candy is $\frac{15}{31}$ × $\frac{9}{30}$ , which equals to $\frac{9}{62}$

The probability of eating two green candies is $\frac{7}{31}$ × $\frac{6}{30}$ which equals to $\frac{7}{155}$

3 0

3 years ago

Verify sine law by taking triangle in 4 quadrant<br>Explain with figure.<br>

Ksivusya [100]

Proof of the Law of Sines

The Law of Sines states that for any triangle ABC, with sides a,b,c (see below)

a

 sin  A

=

b

 sin  B

=

c

 sin  C

For more see Law of Sines.

Acute triangles

Draw the altitude h from the vertex A of the triangle

From the definition of the sine function

 sin  B =

h

c

a n d  sin  C =

h

b

or

h = c  sin  B a n d h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Repeat the above, this time with the altitude drawn from point B

Using a similar method it can be shown that in this case

c

 sin  C

=

a

 sin  A

Combining (4) and (5) :

a

 sin  A

=

b

 sin  B

=

c

 sin  C

- Q.E.D

Obtuse Triangles

The proof above requires that we draw two altitudes of the triangle. In the case of obtuse triangles, two of the altitudes are outside the triangle, so we need a slightly different proof. It uses one interior altitude as above, but also one exterior altitude.

First the interior altitude. This is the same as the proof for acute triangles above.

Draw the altitude h from the vertex A of the triangle

 sin  B =

h

c

a n d  sin  C =

h

b

or

h = c  sin  B a n d h = b  sin  C

Since they are both equal to h

c  sin  B = b  sin  C

Dividing through by sinB and then sinC

c

 sin  C

=

b

 sin  B

Draw the second altitude h from B. This requires extending the side b:

The angles BAC and BAK are supplementary, so the sine of both are the same.

(see Supplementary angles trig identities)

Angle A is BAC, so

 sin  A =

h

c

or

h = c  sin  A

In the larger triangle CBK

 sin  C =

h

a

or

h = a  sin  C

From (6) and (7) since they are both equal to h

c  sin  A = a  sin  C

Dividing through by sinA then sinC:

a

 sin  A

=

c

 sin  C

Combining (4) and (9):

a

 sin  A

=

b

 sin  B

=

c

 sin  C

7 0

3 years ago

Kelko, Boris, and Hong have a total of $83 in their wallets. Hong has 2 times what Boris has. Kelko has $7 more than Boris. How

olasank [31]

Hong has $38. Boris has $19. Kelko has $26

4 0

3 years ago

Consider the graph of the function f(x)=2x.

77julia77 [94]

Given:

The parent function is:

$f(x)=2^x$

The other function is:

$g(x)=2f(x)$

To find:

The statement that describes a key feature of function g.

Solution:

We have,

$f(x)=2^x$

$g(x)=2f(x)$

Using these two functions, we get

$g(x)=2(2)^x$

Putting $x=0$ , we get

$g(x)=2(2)^{(0)}$

$g(x)=2(1)$

$g(x)=2$

The y-intercept of the function g at (0,2). So, option A is correct and option B is incorrect.

We know that $g(x)\to 0$ as $x\to -\infty$ and it will never intersect the line $y=0$ . It means the horizontal asymptote of the function g is

Therefore, the correct option is A.

3 0

2 years ago

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Help me I will give brainliest to whoever is correct

pshichka [43]

Answer:

i did this before

Step-by-step explanation:

the answer is C

5 0

3 years ago

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