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alexdok [17]
4 years ago
13

A merchant in Katmandu sells you a solid gold 1.00-kg statue for a very reasonable price. When you get home, you wonder whether

or not you got a bargain, so you lower the statue into a container of water and measure the volume of displaced water.
A) Find the volume of water that will be displaced for pure gold.
B) For my answer I found 51813 kg/m^3. It marked me down saying enter your answer using dimension of volume.... i thought kg/m^3 was dimesnsion of volume?
Physics
1 answer:
White raven [17]4 years ago
7 0

Answer:

a) 51.8 cm³

b) kg/m³ is a dimension of density (mass/volume). The regular unitys for volume are m³, cm³, L, gallons.

Explanation:

a) The density of pure gold is 19.3 g/cm³. When put in water, the piece of gold will occupy a volume, so that the volume of water will be displaced. To know the volume, we must divide the mass for the density (mass must be in grams because of the units of the density)

V = 1000/19.3

V = 51.8 cm³

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The particle moves with constant speed in a circular path, so its acceleration vector always points toward the circle's center.

At time t_1, the acceleration vector has direction \theta_1 such that

\tan\theta_1=\dfrac{4.00}{6.00}\implies\theta_1=33.7^\circ

which indicates the particle is situated at a point on the lower left half of the circle, while at time t_2 the acceleration has direction \theta_2 such that

\tan\theta_2=\dfrac{-6.00}{4.00}\implies\theta_2=-56.3^\circ

which indicates the particle lies on the upper left half of the circle.

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Recall that

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8 0
3 years ago
2 b (ignore what I already completed)
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Answer:

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A jet aircraft with a mass of 4,475 kg has an engine that exerts a force (thrust) equal to 60,800 N. (a) What is the jet's accel
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Answer:

a) 13.59 m/s²

b) 67.95 m/s

c) 169.875 m

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t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

m = Mass

Force

F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{60800}{4475}\\\Rightarrow a=13.59\ m/s^2

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v=u+at\\\Rightarrow v=0+13.59\times 5\\\Rightarrow v=67.95\ m/s

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v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{67.95^2-0^2}{2\times 13.59}\\\Rightarrow s=169.875\ m

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