Answer:
3
Explanation:
calcium (Ca)
carbon(C)
oxygen(O)
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We are given with the reaction HCOOH(g) →CO2(g) + H2 (g). According to Dalton's law, the total pressure of a vessel is equal to the sum of the partial pressure of the components inside it. In this case, we plot first the data ln (ratio partial pressure of HCOOH to total pressure) vs time. Partial pressure is the difference of pressure (from one point to another). In this case, the equation is ln P(HCCOH) = -0.0146t - 0.2281 where R² = 0.9923. K is equal to <span> -0.0146 s-1. When the total pressure is 291, ln P is -0.66938, thus the time is 30.23 seconds. The half life is ln(0.5)/k equal to 47.46 seconds.</span>
The balanced chemical reaction is:
<span>2 I2 + KIO3 + 6 HCl ---------> 5 ICl + KCl + 3 H2O
</span>
We are given the amount of the product to be produced from the reaction. This will be the starting point of our calculations.
28.6 g ICl (1 mol / 162.35 g ICl ) ( 2 mol I2 / 5 mol ICl ) ( 253.81 g I2 / 1 mol I2 ) = 17.88 g I2
Oxidizing acids, such as nitric acid, can explode when mixed with what type of incompatible chemicals like alcohol, or charcoal.
An oxidizing acid is a Brønsted acid that is a strong oxidizing agent. most Brønsted acids can act as oxidizing agents because the acidic proton can be reduced to hydrogen gas. a few acids include other structures that act as stronger oxidizing agents than hydrogen ions.
Oxidizing acids include concentrated perchloric acid, nitric acid, iodic acid, chromic acid, and the glass cleansing mixture of chromium trioxide and sulfuric acid.
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The moles of water that are produced from 373 moles of ammonia present in any chemical reaction is 746 moles.
<h3>What is the stoichiometry?</h3>
Stoichiometry of the reaction gives idea about the amount of entities present in any chemical reaction before and after the reaction.
Given chemical reaction is:
3Al + 3NH₄ClO₄ → Al₂O₃ + AlCl₃ + 3NO + 6H₂O
From the stoichiometry of the reaction it is clear that:
3 moles of Al = produces 6 moles of H₂O
373 moles of Al = produces 6/3×373 = 746 moles of H₂O
Hence required moles of water is 746 moles.
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