Adapted to the climate change, pollution
Answer:
The answer to your question is: 2 grams of methane
Explanation:
Data
V = 9.15 l
P = 1.77 atm
T = 57° C = 330 °K
Ar mass = 19 g
CH4 mass = ?
Formula
PV = nRT
Process



n = 0.6
Argon
40 g of Ar -------------------- 1 mol
19 g --------------------- x
x = 0.475 mol of Ar
moles of CH4 = 0.6 - 0.475
= 0.125
Methane
16 g of CH4 --------------- 1mol
x ---------------- 0.125 mol
x = 2 grams
1)
Volume = 19 / 1000 = 0.019 L
n = M * V
n = 0.100 * 0.019
n = 0.0019 moles
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2)
M₁ * V₁ = M₂* V₂
5.0 * V₁ = 1.0 * 152
5.0 V₁ = 152
V₁ = 152 / 5.0
V₁ = 30.4 mL
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<span>hope this helps!</span>
My answer will be C. Law of Original lateral continuity. :)
Glucose is used by intestinal cells and red blood cells, while the rest reaches the liver, adipose tissue and muscle cells, where it is absorbed and stored as glycogen.
(it is saved to be used later)