4FeS2 + 11O2-> 2Fe2O3 + 8SO2
Not sure.... I think this is it
Answer:
3.18 (w/w) %
Explanation:
In the problem, you can find mass of NaClO knowing the reaction of NaClO with Na₂S₂O₃ is:
NaClO + 2Na₂S₂O₃ + H₂O → NaCl + Na₂S₄O₆ +2NaOH + NaCl
<em>Where 1 mole of NaClO reacts with 2 moles of Na₂S₂O₃</em>
<em> </em>Moles of thiosulfate in the titration are:
0.0101L ₓ (0.042mol / L) = 4.242x10⁻⁴ moles of Na₂S₂O₃
Thus, moles of NaClO in the initial solution are:
4.242x10⁻⁴ moles of Na₂S₂O₃ ₓ (1mol NaClO / 2 mol Na₂S₂O₃) = 2.121x10⁻⁴ moles NaClO
As molar mass of NaClO is 74.44g/mol, mass of 2.121x10⁻⁴ moles are:
2.121x10⁻⁴ moles ₓ (74.44g / mol) = <em>0.0158g of NaClO</em>
As mass of bleach is 0.496g, mass percent is:
0.0158g NaClO / 0.496g bleach ₓ 100 =
<h3>3.18 (w/w) % </h3>
Answer:
0.1 M is the answer and I have explained it in the attachment below.
Hope this helped!
I say B. Why? because the heat will keep on moving in molecules until it reaches same temperature
The ccs required if methylprednisolone is available as 10 mg/2 cc is 11642.4 mcg
- Here for 100 units of heparin 1 ml is required. Now for forty units of heparin (1/100)*40ml = 0.4ml of heparin is required.
- For 10mg of methylprednisolone, 2mL is required. So for 5.0mg of methylprednisolone, (2/10)×5.0 mL = 1 mL is required.
- For 125mg(0.125g) vancomycin, 1mL is required.So for 0.25g vancomycin, (1/0.125)×0.25mL = 2mL is required.
- For 1kilogram per minute, the doctor ordered 2mcg of propofol.
- For 10kilogram per minute, the doctor ordered 20mcg of propofol.
- Now, for 44lb(= 44×2.205kg) per minute the doctor has to order 44×2.205×2 mcg = 194.04mcg of propofol .
- So now per hour, the 44lb patient requires 194.04×60mcg = 11642.4 mcg of propofol.
To learn more about propofol visit:
brainly.com/question/13606920
#SPJ1
