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3 years ago

What is diatomic gas?

Chemistry

2 answers:

Anika [276]3 years ago

7 0

Molecules composed of only two atoms of the same or different chemical elements

Ann [662]3 years ago

3 0

Gases in which the molecules that make it up naturally consist of two atoms of the same type.

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3 years ago

Would copper exist in a monatomic form, <br> a lattice or as molecules?

Elan Coil [88]

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3 years ago

If an object is red, what type of light is being absorbed by the material?

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3 years ago

Calculate by (a)% weight and (b) %mole each of the elements present in sugar

Musya8 [376]

Explanation:

Molecular mass of sugar = $C_{12}H_{22}O_{11}$ : = 432 g/mol

Atomic mass of carbon atom = 12 g/mol

Atomic mass of hydrogen atom = 1 g/mol

Atomic mass of oxygen atom = 16 g/mol

a) Percentage of an element in a compound:

$\frac{\text{Number of atoms of element}\times \text{Atomic mass of element}}{\text{molecular mass of compound}}\times 100$

Percentage of carbon by weight in $C_{12}H_{22}O_{11}$ :

$\frac{12\times 12 g/mol}{342 g/mol}\times 100=42.10\%$

Percentage of hydrogen by weight in $C_{12}H_{22}O_{11}$ :

$\frac{22\times 1g/mol}{342 g/mol}\times 100=6.43\%$

Percentage of oxygen by weight in $C_{12}H_{22}O_{11}$ :

$\frac{11\times 16g/mol}{342 g/mol}\times 100=51.46\%$

b) Percentage of mole each of the elements present in sugar:

= $\frac{\text{Moles of atoms of an element}}{\text{total moles of all types of atoms}}\times 100$

In mole of sugar we have 12 moles of carbon atom , 22 moles of hydrogen atoms and 11 moles of oxygen atoms.

Percentage of carbon by mole in $C_{12}H_{22}O_{11}$ :

$\frac{12 mol}{45 mol}\times 100=26.66\%$

Percentage of hydrogen by mole in $C_{12}H_{22}O_{11}$ :

$\frac{22 mol}{45 mol}\times 100=48.88\%$

Percentage of oxygen by mole in $C_{12}H_{22}O_{11}$ :

$\frac{11 mol}{45 mol}\times 100=24.44\%$

7 0

4 years ago

In the reaction Mg (s) + 2HCl (aq) H2 (g) + MgCl2 (aq), how many grams of hydrogen gas will be produced from 125.0 milliliters o

Murrr4er [49]

Since the Mg is in excess, therefore HCl will be fully consumed in the reaction.

The first step is to find the amount of HCl in mol

Let N (HCl) = amount of HCl in mol

N (HCl) = (6 mol HCL/L solution) *( 125 mL ) * (1 L/1000 mL) = 0.75 mol of HCl

Through stoichiometry

N (H2) = 0.75 mol HCl * (1 mol H2/ 2 mol of HCl)

N(H2) = 0.375 mol H2

Since we are asked for the number of grams of H2 (mass), we multiply this with the molar mass of hydrogen

M (H2) = 0.375 mol H2 ( 2 g H2 / 1 mol H2)

M (H2) = 0.75 g H2

6 0

4 years ago