1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kotykmax [81]
2 years ago
5

What is the answer to -10+(-3)

Mathematics
2 answers:
Arturiano [62]2 years ago
6 0

Answer:-13

Step-by-step explanation:

aniked [119]2 years ago
5 0

Answer:

-13 would be your answer. Hope this helps!

You might be interested in
Solve for Y 5x-3y=18
Sedbober [7]

Answer:

4

Step-by-step explanation:

4-2

4 0
2 years ago
Read 2 more answers
Which values of m and b will create a system of linear equations with no solution?
kirill115 [55]
Are there value options?

7 0
3 years ago
Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa
xxMikexx [17]

Answer:

\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.221)=0.000067

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example \alpha=0.05, we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins.   Yes   No  Total

Small                                      32   18    50

Medium                                 68     7    75

Large                                     89    11    100

_____________________________________

Total                                     189    36   225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1:  NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*189}{225}=42

E_{2} =\frac{50*36}{225}=8

E_{3} =\frac{75*189}{225}=63

E_{4} =\frac{75*36}{225}=12

E_{5} =\frac{100*189}{225}=84

E_{6} =\frac{100*36}{225}=16

And the expected values are given by:

Size Company/ Heal. Ins.   Yes   No  Total

Small                                      42    8    50

Medium                                 63     12    75

Large                                     84    16    100

_____________________________________

Total                                     189    36   225

And now we can calculate the statistic:

\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(2-1)=2

And we can calculate the p value given by:

p_v = P(\chi^2_{2} >19.221)=0.000067

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example \alpha=0.05, we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

3 0
3 years ago
What is the value of x in degrees?
Brums [2.3K]
180-55-39=86
x=86
Hope it helps
3 0
3 years ago
Pablo tiene $150 pesos, se gastó la tercera parte de su dinero el domingo, y el lunes se gastó las 2/5
sergeinik [125]

Answer:

Step-by-step explanation:

3 0
2 years ago
Other questions:
  • PLEASE CAN ANYONE HELP ME? I'M SO STUCK. I WILL GIVE BRAINLIEST! 5 STARS AND A THANKS!
    10·2 answers
  • PLEASE HELP IM SUPER CONFUSED!! WILL CROWN BRAINLIEST
    13·1 answer
  • The price of a visit to the dentist is calculated according to the formula 50+100n where n is the number of cavities the dentist
    10·1 answer
  • Triangle ABC ​is transformed with the center of dilation at the origin.
    10·1 answer
  • Pls help!! if f(x) = 2x^2-4x and g(x)=5-2x, evaluate f(x) - g(x) for x=5
    8·1 answer
  • 100 POINTS BRAINLIEST QUESTION ATTACHED
    12·2 answers
  • You worked the following hours this week: Monday 8 AM to 5 PM, Tuesday 9 AM to 3 PM, Thursday 8:30 AM to 2:15 PM. You get a 30-m
    7·2 answers
  • Help me please I’m really struggling
    11·1 answer
  • Question 20 (5 points)
    6·1 answer
  • The points A, B and C in 3D space are such that:
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!