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Veseljchak [2.6K]
3 years ago
15

8(2x-14)+13=4x-27 I need help

Mathematics
2 answers:
myrzilka [38]3 years ago
8 0

Answer:

12/70

Step-by-step explanation:

expand brackets

16x-112 + 13 = 4x-27

16x - 99 = 4x-27

16x= 4x + 70

12x=70

x = 12/70

Misha Larkins [42]3 years ago
4 0
Since
−
2
1
1
=
−
1
0
8
−211=−108 is false, there is no solution.
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What is the answer to this math equation(x+5)(x²-3x)​
Nikolay [14]

Answer:

x=-5\\x=0\\x=3

Step-by-step explanation:

I assume your equation to solve is

(x+5)(x^2-3x)=0

When we have a product of two factors equal to zero,

A\cdot B = 0

The solution is either A = 0 or B = 0.

In this case, this means that we can break the equation into two equations:

x+5=0\\x^2-3x=0

Solving the first one, we get:

x+5=0 \rightarrow x = -5

For the second one, we rewrite it as:

x^2-3x=0\\x(x-3)=0

And we see that this equation has two solutions:

x=0\\x=3

Therefore, the three solutions are:

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8 0
3 years ago
(7 points) Cars arrive at a toll both according to a Poisson process with mean 80 cars per hour. If the attendant makes a two-mi
saveliy_v [14]

Answer:

The probability that at least 1 car arrives during the call is 0.9306

Step-by-step explanation:

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If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67   X ≅ Poisson (λ = 2.67)

Now, we find the probability: P(X≥1)

P(X≥1) = 1 - p(x < 1)

P(X≥1) = 1 - p(x=0)

P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!

P(X≥1) = 1 - e^-2.67

P(X≥1) = 1 - 0.06945

P(X≥1) = 0.93055

P(X≥1) = 0.9306

Thus, the probability that at least 1 car arrives during the call is 0.9306.

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3 years ago
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