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Aleonysh [2.5K]

3 years ago

12

If a child pulls a sled through the snow on a level path with a force of 80 N exerted at an angle of 44° above the horizontal, f

ind the horizontal and vertical components of the force. (Give your answers correct to one decimal place.)

1 answer:

Ilya [14]3 years ago

7 0

Answer:

Horizontal component of force = $57.5N$

Vertical component of force= $55.6N$

Explanation:

We are given that

Force=80 N

$\theta=44^{\circ}$

We have to find the horizontal and vertical components of the force.

We know that

Horizontal component of force= $Fcos\theta$

Vertical component of force= $Fsin\theta$

Using the formula

Horizontal component of force = $80cos44^{\circ}$

Horizontal component of force = $57.5N$

Vertical component of force= $80sin44^{\circ}$

Vertical component of force= $55.6N$

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At the end of a delivery ramp, a skid pad exerts a constant force on a package so that the package comes to rest in a distance d

MatroZZZ [7]

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increases by a factor of $\sqrt{2}$

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First we need to find the initial velocity for it to stop at the distance 2d using the following equation of motion:

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where v = 0 m/s is the final velocity of the package when it stops, $v_0$ is the initial velocity of the package when it, a is the deceleration, and $\Delta s = d$ is the distance traveled.

So the equation above can be simplified and plug in Δs = d, $v_0 = v_1$ for the 1st case

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For the 2nd scenario where the ramp is changed and distance becomes 2d, $v_0 = v_2$

$-v_2^2 = 4ad$ (2)

let equation (2) divided by (1) we have:

$\left(\frac{v_2}{v_1}\right)^2 = 4ad / 2ad = 2$

$v_2 / v_1 = \sqrt{2}$

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7 0

4 years ago

A girl and her bicycle have a total mads of 42 kg. At the top of the hill her speed is 4 m/s. The hill is 14.3m high and 112m lo

frosja888 [35]

Answer:

13.78 m/s

Explanation:

Given that:

The mass of the girl & her bicycle = 42 kg

The speed at the top of the hilll= 4 m/s

The height of the hill = 14.3 m

The length of the hill (distance) = 112 m

The frictional force = 20 N

To find the speed at the bottom of the hill; we need to carry out the following processes.

The workdone by gravity = mass × acceleration due to gravity × Δh

= 42 × 9.8 × ( 14.3 - 0 )

= 5885.88 joules

The workdone by the friction = Force × distance = - 20 × 112 (since she is riding down the hill)

The workdone by the friction = -2240 Joules

The initial Kinetic friction = 1/2 mv²

= 1/2 × 42 × 4²

= 336 Joules

The final kinetic energy = Initial Kinetic energy + total work

The final kinetic energy = (336 + 5885.88 - 2240) Joules

The final kinetic energy = 3981.88 Joules

Using the final kinetic energy = 1/2 mv²

3981.88 = 1/2 × 42 × v²

3981.88 = 21 v²

v² = 3981.88/21

v² =189.61

v = $\sqrt{189.61}$

v = 13.78 m/s

Therefore, the speed at the bottom = 13.78 m/s

4 0

3 years ago