In a simple 2-bulb series circuit, why does the bulb light when you close the switch?

Suppose you have 20% of 20/100 or 1/5. Describe how you can solve the problem using 1/5 instead of 20%.

grin007 [14]

Answer:

To calculate Percent in fraction You need to do following steps.

Divide number by 100.

=20/100

=1/5

6 0

3 years ago

Read 2 more answers

A car is sitting still. It accelerates to a constant speed then it decelerates again to zero speed. While the car is acceleratin

Kobotan [32]

Answer:

in the acceleration process the quantity α and w must increase

the deceleration process the alpha quantity must constant a direction opposite to the angular velocity

Explanation:

Acceleration and angular velocity are related to linear

v = w xr

a = αx r

The bold letters indicate vectors and the cross is a vector product, therefore if

we can see that the relationship between linear and angular variables is direct

therefore in the acceleration process the quantity α and w must increase as well as their linear counterparts

in the deceleration process the alpha quantity must constant as the linear acceleration and must have a direction opposite to the angular velocity

5 0

4 years ago

Homework B5

nydimaria [60]

Answer:

I hope this helps a little bit.

7 0

3 years ago

What is the orbital period of a spacecraft in a low orbit near the surface of mars? The radius of mars is 3.4×106m.

valkas [14]

<h2>Answer: 56.718 min</h2>

Explanation:

According to the Third Kepler’s Law of Planetary motion<em> </em><em>“The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”. </em>

In other words, this law states a relation between the orbital period $T$ of a body (moon, planet, satellite) orbiting a greater body in space with the size $a$ of its orbit.

This Law is originally expressed as follows:

$T^{2}=\frac{4\pi^{2}}{GM}a^{3}$ (1)

Where;

$G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

$M=6.39(10)^{23}kg$ is the mass of Mars

$a=3.4(10)^{6}m$ is the semimajor axis of the orbit the spacecraft describes around Mars (assuming it is a <u>circular orbit </u>and a <u>low orbit near the surface </u>as well, the semimajor axis is equal to the radius of the orbit)