Answer:
The distance between interference fringes increases.
Explanation:
In a double-slit diffraction pattern, the distance of the n-order fringe from the centre of the pattern is
where 
is the wavelength of the light, D the distance of the screen, and d the separation between the slits.
If we take two adjacent fringes, n and (n+1), their distance is
so, we see that it is inversely proportional to the slit separation, d.
Therefore, if the separation between the slits decreases, the distance between the interference fringes increases.
Explanation:
Use half life equation:
A = A₀ (½)^(t / T)
where A is the final amount,
A₀ is the initial amount,
t is time,
and T is half life.
0.375 = 3 (½)^(1 / T)
0.125 = (½)^(1 / T)
(½)^3 = (½)^(1 / T)
3 = 1 / T
T = 1/3 hours
T = 20 minutes
Answer:
sorry I've never took in this class before I will not be able to help you
In our solar system, terrestrial planets are separated from the gas giants by the asteroid belt. The asteroid belt is a region in the solar system between Mars and Jupiter where asteroids are located. Gas giants do not have a solid surface and possible a small rocky core. The gas giants are Jupiter, Saturn, Uranus and Neptune. The first four planets, Mercury, Venus, Earth and Mars.
Answer:
The magnitude of the average induced emf in the wire during this time is 9.533 V.
Explanation:
Given that,
Radius r= 0.63 m
Magnetic field B= 0.219 T
Time t= 0.0572 s
We need to calculate the average induce emf in the wire during this time
Using formula of induce emf
.....(I)
In reshaping of wire, circumstance must remain same.
We calculate the length when wire is in two loops
The length when wire is in one loop
We need to calculate the initial area
Put the value into the formula
The final area is
Put the value of initial area and final area in the equation (I)
Negative sign shows the direction of induced emf.
Hence, The magnitude of the average induced emf in the wire during this time is 9.533 V.
