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HACTEHA [7]
3 years ago
5

The potential difference between two points, A and B, in an electric field is 2.00 volts. The energy required to move a charge o

f 8x10^-19 coulomb from point A to point B is
Physics
1 answer:
Pavlova-9 [17]3 years ago
6 0

Answer:

W_A_B=-1.6\times 10^{-18} J

Explanation:

Let A and B be two points located in a uniform electric field, A being a distance d from B in the direction of the field. The work that an external force must do to bring a unit positive charge q from the reference point to the point considered against the electric force at constant speed, mathematically is expressed by:

V_B_A=\frac{W_A_B}{q}

Therefore, isolating W_A_B and replacing the data provided:

W_A_B=V_B_A *q=-2*(8\times 10^{-19}) =-1.6\times 10^{-18}J

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