Question

The potential difference between two points, A and B, in an electric field is 2.00 volts. The energy required to move a charge of 8x10^-19 coulomb from point A to point B is

Answer 1

Answer:

$W_A_B=-1.6\times 10^{-18} J$

Explanation:

Let A and B be two points located in a uniform electric field, A being a distance d from B in the direction of the field. The work that an external force must do to bring a unit positive charge q from the reference point to the point considered against the electric force at constant speed, mathematically is expressed by:

$V_B_A=\frac{W_A_B}{q}$

Therefore, isolating $W_A_B$ and replacing the data provided:

$W_A_B=V_B_A *q=-2*(8\times 10^{-19}) =-1.6\times 10^{-18}J$