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HACTEHA [7]
3 years ago
5

The potential difference between two points, A and B, in an electric field is 2.00 volts. The energy required to move a charge o

f 8x10^-19 coulomb from point A to point B is
Physics
1 answer:
Pavlova-9 [17]3 years ago
6 0

Answer:

W_A_B=-1.6\times 10^{-18} J

Explanation:

Let A and B be two points located in a uniform electric field, A being a distance d from B in the direction of the field. The work that an external force must do to bring a unit positive charge q from the reference point to the point considered against the electric force at constant speed, mathematically is expressed by:

V_B_A=\frac{W_A_B}{q}

Therefore, isolating W_A_B and replacing the data provided:

W_A_B=V_B_A *q=-2*(8\times 10^{-19}) =-1.6\times 10^{-18}J

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seraphim [82]

Answer:

The value of acceleration that accomplishes this is 8.61 ft/s² .

Explanation:

Given;

maximum distance to be traveled by the car when the brake is applied, d = 450 ft

initial velocity of the car, u = 60 mph = (1.467 x 60) = 88.02 ft/s

final velocity of the car when it stops, v = 0

Apply the following kinematic equation to solve for the deceleration of the car.

v² = u² + 2as

0 = 88.02² + (2 x 450)a

-900a = 7747.5204

a = -7747.5204 / 900

a = -8.61 ft/s²

|a| = 8.61 ft/s²

Therefore, the value of acceleration that accomplishes this is 8.61 ft/s² .

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3 years ago
What is the speed of the animal from 0-20s? <br><br> 50 m/s<br> 0.4 m/s<br> 20 m/s<br> 2.5 m/s
Shkiper50 [21]

Answer:

2.5 m/s

Explanation:

The speed of the animal is given by the ratio between the distance travelled by the animal and the time elapsed:

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In the time interval 0-20 s, we have

d = 50 m - 0 m = 50 m

t = 20 s - 0 s = 20 s

So, the speed is

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3 years ago
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Answer:

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Explanation:

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