Answer:
V₂ = 12.43 L
Explanation:
Given data:
Initial pressure = 650 KPa
Initial volume = 2.2 L
Final pressure = 115 KPa
Final volume = ?
Solution:
The given problem will be solved through the Boyles law,
"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"
Mathematical expression:
P₁V₁ = P₂V₂
P₁ = Initial pressure
V₁ = initial volume
P₂ = final pressure
V₂ = final volume
Now we will put the values in formula,
P₁V₁ = P₂V₂
650 KPa ×2.2 L = 115 KPa × V₂
V₂ = 1430 KPa. L/ 115 KPa
V₂ = 12.43 L
Answer:
the answer would be C of not C is B
Answer : The value of rate of reaction is 
Explanation :
Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
The given chemical equation is:

Rate law expression for the reaction is:
![\text{Rate}=k[NO]^a[O_2]^b](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5Ea%5BO_2%5D%5Eb)
As per question,
a = order with respect to
= 2
b = order with respect to
= 1
Thus, the rate law becomes:
![\text{Rate}=k[NO]^2[O_2]^1](https://tex.z-dn.net/?f=%5Ctext%7BRate%7D%3Dk%5BNO%5D%5E2%5BO_2%5D%5E1)
Now, calculating the value of rate of reaction by using the rate law expression.
Given :
k = rate constant = 
[NO] = concentration of NO = 
= concentration of
= 
Now put all the given values in the above expression, we get:


Hence, the value of rate of reaction is 