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Naya [18.7K]
3 years ago
5

32g of sulfur will react with48g of oxygen to produce 80g of sulfur trioxide. If 16g of sulfur and 100g of oxygen are placed int

o a sealed container and allowed to react, what is the mass of the material in the container after the reaction is complete?
Chemistry
1 answer:
Mkey [24]3 years ago
3 0

Write a balanced equation to find the mass of product using stoichiometryShare this answer and help others!

2g of sulfur will react with 3g of oxygen to produce 5g of sulfur trioxide.  If 32g of sulfur and 100g of oxygen are placed into a sealed container and allowed to react, how much sulfur dioxide will be produced?

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The balanced equation between the H_2SO_4 and NaHCO_3 is:

H_2SO_4+2NaHCO_3\rightarrow Na_2SO_4+2CO_2+2H_2O

Formula of molarity is:

Molarity = \frac{Moles of solute}{Volume of solution in Liters}

Molarity = 6.0 M, Volume = 35 mL = 0.035 L

Substituting the values,

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Moles of solute = 0.035 L\times 6 mol/L = 0.21 mole

So, number of moles of H_2SO_4 is 0.21 mole.

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Molar mass of NaHCO_3 = 84.007 g/mol

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