MIDDLE SCHOOL: What are the three types of energy used when cleaning? (Please write them in order of occurrence)

What is accurate about the planet’s climate system?

ElenaW [278]

The accurate about the planet’s climate system is the wind

because heating near the equator blows the wind to drive the convection cells in the atmosphere, and the friction created by the rotation of the spherical planet in the atmosphere causes the wind to appear to bend left or right across the surface of the planet. ..

The climate system is a highly complex global system consisting of five major components: the atmosphere, the ocean, the cryosphere (cryosphere), the land surface, the biosphere, and the interactions between them.

Solar energy drives the climate by heating the surface of the earth unevenly. Ice also reflects incoming sunlight, further cooling the poles. Temperature differences move the ocean and atmosphere as they work together to disperse heat throughout the globe.

Learn more about the planet’s climate system here:brainly.com/question/15351986

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6 0

1 year ago

The speed of sound at temperature of________in the air is 360m/s.

Aleks04 [339]

Vo= 331+0.6T

360=331+0.6T

360-331=0.6T

29=0.6T

0.6T/29

T=6/290 so change it to simplest form and us formulas good luck

4 0

2 years ago

Read 2 more answers

The maximum speed with which you can throw a stone is about 20 m/s. Can you hit a window 45 m away horizontally and 10 m up from

Allushta [10]

Answer:

y = 17 m

Explanation:

For this projectile launch exercise, let's write the equation of position

x = v₀ₓ t

y = $v_{oy}$ t - ½ g t²

let's substitute

45 = v₀ cos θ t

10 = v₀ sin θ t - ½ 9.8 t²

the maximum height the ball can reach where the vertical velocity is zero

v_{y} = v_{oy} - gt

0 = v₀ sin θ - gt

0 = v₀ sin θ - 9.8 t

Let's write our system of equations

45 = v₀ cos θ t

10 = v₀ sin θ t - ½ 9.8 t²

0 = v₀ sin θ - 9.8 t

We have a system of three equations with three unknowns for which it can be solved.

Let's use the last two

v₀ sin θ = 9.8 t

we substitute

10 = (9.8 t) t - ½ 9.8 t2

10 = ½ 9.8 t2

10 = 4.9 t2

t = √ (10 / 4.9)

t = 1,429 s

Now let's use the first equation and the last one

45 = v₀ cos θ t

0 = v₀ sin θ - 9.8 t

9.8 t = v₀ sin θ

45 / t = v₀ cos θ

we divide

9.8t / (45 / t) = tan θ

tan θ = 9.8 t² / 45

θ = tan⁻¹ ( 9.8 t² / 45 )

θ = tan⁻¹ (0.4447)

θ = 24º

Now we can calculate the maximum height

v_y² = $v_{oy}^2$ - 2 g y

vy = 0

y = v_{oy}^2 / 2g

y = (20 sin 24)²/2 9.8

y = 3,376 m

the other angle that gives the same result is

θ‘= 90 - θ

θ' = 90 -24

θ'= 66'

for this angle the maximum height is

y = v_{oy}^2 / 2g

y = (20 sin 66)²/2 9.8

y = 17 m

thisis the correct

6 0

3 years ago

ASAP HELPPPPPP POP PLEASE

drek231 [11]

Answer:

The answer is in the attachment

Explanation:

!!PLEASE PLEASE PLEASE PLEASE PLEASE MARK ME THE BRAINLIEST!!

5 0

1 year ago

The electric potential in a region of space is \[V=350/\sqrt{x ^{2}+y ^{2}}\] where x and y are in meters. what is the strength

VARVARA [1.3K]

So the given value or the formula in getting the electric potential region of space is V=350/sqrt of x^2+y^2. So the given data is x and y is equals to 2.6 and 2.8. So in my calculation i came up with an answer of 91.6

8 0

3 years ago