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svetlana [45]
3 years ago
6

In this diagram,the distance known as the amplitude is shown by choice

Physics
2 answers:
max2010maxim [7]3 years ago
5 0

Answer:

B

Explanation:

the amplitude is the distance from the resting point to the crest/trough.

Alenkasestr [34]3 years ago
5 0

Answer:

For those who are still confused the answer is B

Explanation:

If you say D it the wavelength but the question ask for distance so it asking whats the distance of the line in the middle to the top of the wave.

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According to Coulomb’s Law, the force between two charged objects is related to _____.
Natasha_Volkova [10]

Answer:

A.) the inverse of the square of the distance separating them

Explanation:

Coulombs law states that "the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them."

Mathematically, F = kq1q2/r²

Where q1 and q2 are the charges

r is the distance between the charges.

According to the law, the force between two charged objects is related to the inverse of the square of the distance separating them.

5 0
3 years ago
Calculate the average power required to lift a 750 N object a vertical distance of 10 meters in 4.0 seconds.
Nina [5.8K]

Answer:

500

Explanation:

5 0
2 years ago
Boat A and Boat B have the same mass. Boat A's velocity is three times greater than that of Boat B. Compared to
Zarrin [17]

Answer:

nine times as much.

Explanation:

K.E of A = 9 times K.E of B

7 0
2 years ago
Read 2 more answers
assuming birdman flies at height of 72m, how fast should he fly to hit bucket at 63m from start of field. gravity is -9.8m/s^2 n
algol [13]

Answer:

.....Birdman?

Explanation:

7 0
3 years ago
If it takes a planet 2.8 × 108 s to orbit a star with a mass of 6.2 × 1030 kg, what is the average distance between the planet a
Levart [38]

Answer:

9.36*10^11 m

Explanation

Orbital velocity  v=√{(G*M)/R},

G = gravitational constant =6.67*10^-11 m³ kg⁻¹ s⁻²,

M = mass of the star

R =distance from the planet to the star.

v=ωR, with ω as the angular velocity and R the radius

ωR=√{(G*M)/R},

ω=2π/T,

T = orbital period of the planet

To get R we write the formula by making R the subject of the equation

(2π/T)*R=√{(G*M)/R}

{(2π/T)*R}²=[√{(G*M)/R}]²,

(4π²/T²)*R²=(G*M)/R,

(4π²/T²)*R³=G*M,

R³=(G*M*T²)/4π²,

R=∛{(G*M*T²)/4π²},

Substitute values

R=9.36*10^11 m

5 0
2 years ago
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