The answer is 12.5 mL.
Solution:
<u>M, 6.00M V₁ =?</u>
M2 = 3.00M, V₂ = 25.0mL
<u>M1V1 = M2 V2/M1</u>
V1 = M2V2 M,
V1 = 25.0X3.00/6.00
∴ V1 = 12.5 mL
The initial concentration of the resulting solution is 2 molar which is the volume multiplied by the concentration. The volume of the starting solution is therefore 2,500 ml × 2.25 mol. Calculate the number of moles of HCl dissolved in a given volume of acid by reacting an acid with CaCO3.
This is essentially a double exchange reaction with the decomposition of one of the products. To determine the amount of stock solution required divide the number of moles of glucose by the molarity of the stock solution.
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The number of calcium atoms that would be in a 100 g sample of calcium is 1.505 x 10²⁴ atoms
<u><em>calculation</em></u>
Step 1 ; find the moles of calcium
moles = mass÷ molar mass
from periodic table the molar mass of Ca =40 g/mol
moles is therefore = 100 g÷ 40 g/mol = 2.5 moles
Step 2: use the Avogadro's law constant to determine the number of atoms of Calcium
That is According Avogadro's law 1 mole = 6.02 × 10²³ atoms
2.5 moles=? atoms
{(2.5 moles × 6.02×10²³ atoms) / 1 mole} = 1.505 × 10²⁴ atoms
Answer:
Lithium has the greatest difference between its first and second ionization energies.