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4 years ago

Summarize how the solar system was devolved and what keeps it in place today

Chemistry

1 answer:

Gemiola [76]4 years ago

6 0

Answer:

Gravitational Pull

Explanation:

Gravitational Pull keeps the solar system in place.

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A student is studying a sample of carbon dioxide gas inside a small syringe. At constant temperature the syringe has a volume of

Soloha48 [4]

The new pressure inside the syringe will be 1.25 atm

At constant temperatures, the volume of a gas is inversely proportional to its pressure.

Thus: P1V1 = P2V2

In this case, P1 = 3.0 atm, V1 = 89.6 mL, V2 = 215 mL

P2 = P1V1/V2

= 3 x 89.6/215

= 1.25 atm

More on gas laws can be found here: brainly.com/question/1190311

4 0

2 years ago

Sulfuric acid dissolves aluminum metal according to the following reaction:

Fiesta28 [93]

Answer:

$m_{H_2SO_4}=81.7gH_2SO_4$

$m_{H_2}=1.67gH_2$

Explanation:

Hello,

Based on the given undergoing chemical reaction is is rewritten below:

$2Al (s) + 3H_2SO_4 (aq)\rightarrow Al _2(SO4)_3 (aq) + 3H_2 (g)$

By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:

$m_{H_2SO_4}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2SO_4}{2molAl}*\frac{98gH_2SO_4}{1molH_2SO_4} \\m_{H_2SO_4}=81.7gH_2SO_4$

Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:

$m_{H_2}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2}{2molAl}*\frac{2gH_2}{1molH_2} \\m_{H_2}=1.67gH_2$

Best regards.

3 0

3 years ago

A sample of gas contains 0.1700 mol of OF2(g) and 0.1700 mol of H2O(g) and occupies a volume of 19.5 L. The following reaction t

andreev551 [17]

Answer: The volume of the sample after the reaction takes place is 29.25 L.

Explanation:

The given reaction equation is as follows.

$OF_{2}(g) + H_{2}O(g) \rightarrow O_{2}(g) + 2HF(g)$

So, moles of product formed are calculated as follows.

$\frac{3}{2} \times 0.17 mol \\= 0.255 mol$

Hence, the given data is as follows.

$n_{1}$ = 0.17 mol, $n_{2}$ = 0.255 mol

$V_{1}$ = 19.5 L, $V_{2} = ?$

As the temperature and pressure are constant. Hence, formula used to calculate the volume of sample after the reaction is as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}$

Substitute the values into above formula as follows.

$\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{19.5 L}{0.17 mol} = \frac{V_{2}}{0.255 mol}\\V_{2} = \frac{19.5 L \times 0.255 mol}{0.17 mol}\\= \frac{4.9725}{0.17} L\\= 29.25 L$

Thus, we can conclude that the volume of the sample after the reaction takes place is 29.25 L.

8 0

3 years ago

a compound is 21.20% nitrogen,6.06% hydrogen, 24,30% sulfur, and 48.45% oxygen. write the empirical formula and name the compoun

IRISSAK [1]

The numbers may be off by a few, if you worked it out, since my periodic table is for AP chemistry. Hope this helps!!!

4 0

4 years ago

How much energy is needed to completely remove an electron from n $ 2 in a hydrogen atom?

NeTakaya

The energy needed to split an atom into separate protons, neutrons, and electrons

7 0

3 years ago