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muminat
3 years ago
7

Why is it more difficult to remove an

Chemistry
1 answer:
Tom [10]3 years ago
3 0
In general, the further away an electron is from the nucleus, the easier it is for it to be expelled. In other words, ionization energy is a function of atomic radius; the larger the radius, the smaller the amount of energy required to remove the electron from the outer most orbital. For example, it would be far easier to take electrons away from the larger element of Ca (Calcium) than it would be from one where the electrons are held tighter to the nucleus, like Cl (Chlorine). Hope this helped a little not the exact answer though :)
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Pls answer 24 and 26.pls explain
vazorg [7]
24- diamond and corundum because they’re harder 26- aapatite fluorite calcite
6 0
3 years ago
a chemist has a block of iron metal (density is 7.87 g/ml). the block weighs 1.90 g. what is the volume of the iron block in ml?
Natali5045456 [20]

The block of iron metal with a density of 7.87 g/mL has a volume in mL of 0.2414 mL

The density formula and the procedure we will use is:

ρ = m/v

Where:

  • v= volume
  • ρ= density
  • m= mass

Information about the problem:

  • m= 1.90 g
  • ρ= 7.87 g /mL
  • v= ?

Applying the density formula and clearing the volume (v), we get:

ρ = m/v

v = m / ρ

v = 1.90 g / 7.87 g/ mL

v = 0.2414 mL

<h3>What is density?</h3>

It is a physical quantity that expresses the ratio of the body mass to the volume it occupies.

Learn more about density in: brainly.com/question/1354972

#SPJ4

6 0
2 years ago
Please help :) Surface currents are caused by ______ . A. differences in water temperature B.high salinity C.differences in dens
PolarNik [594]
Surface current are caused by : D. Wind Forces.
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3 0
3 years ago
Read 2 more answers
The diagonals of a rhombus are 6 and 8. The area of the rhombus is 20 24 48
Serhud [2]

Answer:

= 24 square units

Explanation:

The area of a rhombus is given by the formula;

Area = pq/2

Where p and q are the diagonals of the rhombus.

In this case; p = 6 and q = 8

Therefore;

Area = (6×8)/2

        = 24 square units

6 0
3 years ago
Read 2 more answers
4. By what quantity must the heat capacity be divided to obtain the specific heat of that material? (I poin
charle [14.2K]

Answer:

its mass

its temperature

Explanation:

The heat capacity of a body is the amount of heat needed to raise that temperature of a body by 1k or 1°C.

It is expresses as:

              H = m c Ф

where m is the mass of the body

           c is the specific heat of the body

           Ф is the temperature change of the body

Specific heat capacity is that heat content needed to raise the temperature of a unit mass of a substance by 1k or 1°C

Heat capacity is also known as heat content;

 To solve the problem:

 since H = m c Ф

  we make the unknown c the subject of the expression;

                c = \frac{H}{m (t_{2} - t_{1} )} = H / mФ

So to obtain the specific heat capacity, divided the heat capacity by mass and its temperature change.

8 0
4 years ago
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