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expeople1 [14]
3 years ago
14

Which of the following techniques can be used to separate a heterogeneous mixture into its component parts?

Chemistry
2 answers:
fredd [130]3 years ago
8 0

Answer:

                  Separation by density

Explanation:

                    Mixtures are made up of two or more pure substances which tends to keep their individual identities. These components can be separated from each other by different physical techniques.

                    Mixtures are further classified as;

  (i)  Homogenous Mixture:

                                            In this type of the mixtures the components are uniformly mixed and their properties as well as composition as uniform throughout. Such mixtures are also called as solutions.

The physical methods used to separate these components from each other are distillation (taking heat and pressure into account), Solvent extraction, Magnetic separation, Chromatography e.t.c.

  (ii)  Homogenous Mixture:

                                            In this type of the mixtures the components are not uniformly mixed and their physical properties and composition are also not uniform.

The physical methods used to separate these components from each other are Filtration, Magnetic Separation, Centrifugation, Flotation e.t.c.

So, in given options the density can play role by settling the massive components of heterogenous mixture to sit at the bottom and separated

Mkey [24]3 years ago
8 0

Answer:

B)

Explanation:

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What is “monomer” mean?
oksano4ka [1.4K]

it is a molecule* that can be joined with other molecules that are identical to form a polymer*

key words :

a molecule:

a group of atoms bonded together, representing the smallest fundamental unit of a chemical compound that can take part in a chemical reaction.

a polymer:

a substance that has a molecular structure consisting chiefly or entirely of a large number of similar units bonded together

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3 years ago
The radius of a uranium atom is 149 pm. How many uranium atoms would have to be laid side by side to span a distance of 4.96 mm?
nikitadnepr [17]

Answer:

4960000000 pm

Explanation:

4.96*1000000000= 4960000000

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How do radiography and sonography compare?
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3 years ago
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has a standard free‑energy change of − 3.59 kJ / mol at 25 °C. What are the concentrations of A , B , and C at equilibrium if, a
Mamont248 [21]

Answer: The concentrations of A , B , and C at equilibrium are 0.1583 M, 0.2583 M, and 0.1417 M.

Explanation:

The reaction equation is as follows.

               A + B \rightarrow C

Initial :     0.3   0.4          0

Change:  -x       -x           x

Equilbm: (0.3 - x)  (0.4 - x)  x  

We know that, relation between standard free energy and equilibrium constant is as follows.

      \Delta G = -RT ln K

Putting the given values into the above formula as follows.

      \Delta G = -RT ln K

      -3.59 kJ/mol = -8.314 \times 10^{-3} kJ/mol K ln (\frac{x}{(0.3 - x)(0.4 - x)})

                x = 0.1417

Hence, at equilibrium

  •  [A] = 0.3 - 0.1417

       = 0.1583 M

  •  [B] = 0.4 - 0.1417

       = 0.2583 M

  •  [C] = 0.1417 M
5 0
3 years ago
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