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Marrrta [24]
2 years ago
15

what is the molecular formula of benzoyl peroxide (c7h5o2) of the molecular mass is 0.242 kg/mol?(show work please)

Chemistry
1 answer:
AfilCa [17]2 years ago
6 0

Answer : The molecular formula of benzoyl peroxide is C_{14}H_{10}O_4

Explanation :

Empirical formula : It is the simplest form of the chemical formula which depicts the whole number of atoms of each element present in the compound.  

Molecular formula : it is the chemical formula which depicts the actual number of atoms of each element present in the compound.  

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

As we are given that the molar mass of compound is, 0.242 kg/mol.

Molecular mass = 0.242 kg/mol = 242 g/mol      (1 kg = 1000 g)

The empirical mass of C_7H_5O_2 = 7(12) + 5(1) + 2(16) = 121 g/eq

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

n=\frac{242}{121}

n=2

Molecular formula = (C_7H_5O_2)_n = (C_7H_5O_2)_2 = C_{14}H_{10}O_4

Thus, the molecular formula of benzoyl peroxide is C_{14}H_{10}O_4

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<h3><u>Answer;</u></h3>

Higher velocity of particles

<h3><u>Explanation;</u></h3>

The diffusion rate is determined by a variety of factors which includes;

  • Temperature such that the higher the temperature, the more kinetic energy the particles will have, so they will move and mix more quickly and the diffusion rate will be high.
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3 years ago
Consider the unbalanced equation for the oxidation of aluminum.
SashulF [63]
In order to balance an equation, we apply the principle of conservation of mass, which states that mass can neither be created nor destroyed. Therefore, the mass of an element before and after a reaction remains constant. Here, the balanced equation becomes:
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The coefficients are 4, 3 and 2.
8 0
2 years ago
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The enthalpy of combustion for octane (C8H18(l)), a key component of gasoline, is -5,074 kJ/mol. This value is the Delta. Hrxn f
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Combustion can be defined as the reaction of a compound with oxygen. The enthalpy of combustion of octane is \Delta H_{\rm rxn} for \rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O.

<h3>What is the enthalpy of reaction?</h3>

The enthalpy of reaction is the amount of heat energy absorbed or lost by the molecules in the chemical reaction.

The enthalpy of combustion is the amount of heat energy released by the compound in the reaction with oxygen.

The reaction in which heat is liberated with the reaction of a compound with oxygen has an enthalpy of combustion, equivalent to the enthalpy of reaction.

The combustion of octane can be given as:

\rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O

Thus, the reaction has combustion energy equivalent to the enthalpy of the reaction is \rm C_8H_{18}\;+\;25\;O_2\;\rightarrow 8\;CO_2\;+\;9\;H_2O. Thus, option B is correct.

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2 years ago
A student uses a solution of 1.2 molar sodium hydroxide (NaOH) to calculate the concentration of a solution of sulfuric acid (H2
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From the calculations, the concentration of the acid is 0.24 M.

<h3>What is neutralization?</h3>

The term neutralization has to do with a reaction in which an acid and a base react to form salt and water only.

We have to use the formula;

CAVA/CBVB = NA/NB

CAVANB =CBVBNA

The equation of the reaction is; 2NaOH + H2SO4 ----> Na2SO4 + 2H2O

CA = ?

CB = 1.2 M

VA =  50 mL

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NA = 1

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CA = CBVBNA/VANB

CA = 1.2 M * 20 mL * 1/ 50 mL * 2

CA = 0.24 M

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5 0
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when the following redoc reaction is balances (assume acidic solution), how many moles of water appear and on what side
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8 moles of water on the right side.

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Redox reactions: the burning of fuels, the corrosion of metals, and even the processes of photosynthesis and cellular respiration involve oxidation and reduction.

Step 1:

MnO4- ----> Mn2+

2Cl- ------> Cl2

Step 2:

MnO4- --> Mn2+ + 4H2O

2Cl- -----> Cl2

Step 3:

8H+ + MnO4- ------> Mn2+ + 4H2O

2Cl- ----->Cl2

Step 4:

8H+ + MnO4- +5e- ------>Mn2+ + 4H2O

2Cl- ----> Cl2+ 2e-

Step 5:

16 H+ +2 MnO4- +10Cl- ----->2 Mn2+ + 8H2O+5Cl2

This is the balanced equation in an acidic medium.

That is 8, right side.

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